Answer : The specific heat of the metal is, 
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of metal = ?
= specific heat of ice = 
= mass of metal = 1.00 kg
= mass of ice = 1.00 kg
= final temperature of mixture = 
= initial temperature of metal = 
= initial temperature of ice = 
Now put all the given values in the above formula, we get:
![(1.00kg)\times c_1\times (-8.88-5.00)^oC=-[(1.00kg)\times 2000J/kg^oC\times (-8.88-(-24.0))^oC]](https://tex.z-dn.net/?f=%281.00kg%29%5Ctimes%20c_1%5Ctimes%20%28-8.88-5.00%29%5EoC%3D-%5B%281.00kg%29%5Ctimes%202000J%2Fkg%5EoC%5Ctimes%20%28-8.88-%28-24.0%29%29%5EoC%5D)
Therefore, the specific heat of the metal is,
The quadratic equation that models the height of the rocket after t seconds is:
s(t) = -4.9t² + 39.2t.
<h3>What is the quadratic function for a projectile's height?</h3>
Considering the height in meters, the equation is given by:
s(t) = -4.9t² + v(0)t + h(0)
In which:
- v(0) is the initial velocity, in m/s.
- h(0) is the initial height, in m.
In this problem, we have that v(0) = 39.2, h(0) = 0, hence the equation is:
s(t) = -4.9t² + 39.2t.
More can be learned about quadratic functions at brainly.com/question/24737967
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Answer: D
Step-by-step explanation: i took a course on this
Answer:
Step-by-step explanation:
(ﾉ◕ヮ◕)ﾉ*:･ﾟ✧
![\dfrac{8}{5} - \left[-\dfrac{2}{3}\right]](https://tex.z-dn.net/?f=%5Cdfrac%7B8%7D%7B5%7D%20-%20%5Cleft%5B-%5Cdfrac%7B2%7D%7B3%7D%5Cright%5D)
