Answer:
If I was you i'll take my chances with 125 degrees.
Answer:
area of rectangle =length ×width
area of rectangle=12yd×15yd
area of rectangle=180yd²
A.
Mice are small and kilograms are for much larger objects. The other two measurements are for liquids.
Options were missing in the question;
A water cup is shaped like a cone. It has a diameter of 3 inches and a slant height of 5 inches. About how many square inches of paper do you need to make a cup? Use 3.14 to approximate pi.
24 square inches
31 square inches
47 square inches
52 square inches
Answer:
24 square inches
Step-by-step explanation:
Given:
Diameter = 3 in
So we can say that;
Radius is half of diameter.
radius (r) = 
Slant height (l) = 5 in
We need to find how many square inches of paper do you need to make a cup.
Solution:
Now according to question we required to find the amount of paper used to make cup.
Also Water cup is shaped liked cone.
Hence we can say that the base of cone is not covered since it will remain open.
So we will use Lateral surface area of the cone to find the paper requirement.
Now we know that;
Lateral surface area of cone is equal to π times radius times slant height.
framing in equation form we get;
Hence We can say that 24 square inches of paper will be needed to make the cup.
16x^2 + 25y^2 + 160x - 200y + 400 = 0 Rearrange and regroup.
(16x^2 + 160x) + (25y^2 - 200y ) = 0-400. Group the xs together and the ys together.
16(X^2 + 10x) + 25(y^2-8y) = -400. Factorising.
We are going to use completing the square method.
Coefficient of x in the first expression = 10.
Half of it = 1/2 * 10 = 5. (Note this value)
Square it = 5^2 = 25. (Note this value)
Coefficient of y in the second expression = -8.
Half of it = 1/2 * -8 = -4. (Note this value)
Square it = (-4)^2 = 16. (Note this value)
We are going to carry out a manipulation of completing the square with the values
25 and 16. By adding and substracting it.
16(X^2 + 10x) + 25(y^2-8y) = -400
16(X^2 + 10x + 25 -25) + 25(y^2-8y + 16 -16) = -400
Note that +25 - 25 = 0. +16 -16 = 0. So the equation is not altered.
16(X^2 + 10x + 25) -16(25) + 25(y^2-8y + 16) -25(16) = -400
16(X^2 + 10x + 25) + 25(y^2-8y + 16) = -400 +16(25) + 25(16) Transferring the terms -16(25) and -25(16)
to other side of equation. And 16*25 = 400
16(X^2 + 10x + 25) + 25(y^2-8y + 16) = 25(16)
16(X^2 + 10x + 25) + 25(y^2-8y + 16) = 400
We now complete the square by using the value when coefficient was halved.
16(x-5)^2 + 25(y-4)^2 = 400
Divide both sides of the equation by 400
(16(x-5)^2)/400 + (25(y-4)^2)/400 = 400/400 Note also that, 16*25 = 400.
((x-5)^2)/25 + ((y-4)^2)/16 = 1
((x-5)^2)/(5^2) + ((y-4)^2)/(4^2) = 1
Comparing to the general format of an ellipse.
((x-h)^2)/(a^2) + ((y-k)^2)/(b^2) = 1
Coordinates of the center = (h,k).
Comparing with above (x-5) = (x - h) , h = 5.
Comparing with above (y-k) = (y - k) , k = 4.
Therefore center = (h,k) = (5,4).
Sorry the answer came a little late. Cheers.
