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viktelen [127]
3 years ago
15

Please help me fill in the blanks asap !!! the first question is a yes or no question. thankyou

Mathematics
1 answer:
sattari [20]3 years ago
4 0

Answer:

No, because the longest side is too short to be the hypotenuse of a right triangle.

Step-by-step explanation:

To see if the sides form a right triangle

6² + 8² = 9²

36 + 64 = 81

100 ≠ 81

The the 3rd side is too short

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

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Answer:

k=\frac{2P}{x^2}


Step-by-step explanation:

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<em>We need to solve for k, so we can perform the steps shown below:</em>

P=\frac{1}{2}kx^2\\P=\frac{kx^2}{2}\\2P=kx^2\\\frac{2P}{x^2}=k


Hence, the third answer choice is correct.

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Answer:

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Step-by-step explanation:

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IgorC [24]
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Hope this helps!

P.S- Can you plz mark min as brainliest??

Thank You
3 0
3 years ago
Can someone help please (highlighted in blue)
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\implies {\blue {\boxed {\boxed {\purple {\sf {B)\:10}}}}}}

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

4 + 3 \: ( \: 10 -  {2}^{3}  \: )

➺\: 4 + 3 \: ( \: 10 - 2 \times 2 \times 2 \: )

➺\: 4 + 3 \: ( \: 10 - 8 \: )

➺\: 4 + 3 \: ( \: 2 \: )

➺\: 4 + 6

➺\: 10

<h3><u>Note</u>:-</h3>

\sf\pink{PEMDAS\: rule.}

P = Parentheses

E = Exponents

M = Multiplication

D = Division

A = Addition

S = Subtraction

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

6 0
3 years ago
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To decrease an amount by 7%, what single multiplier should you use?
notka56 [123]
To decrease an amount by 7%  what single multiplier would you use.  You  want 7% less than 100%, so the answer is (100%-7%)=93% =0.93. Hope I helped! 
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