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AysviL [449]
3 years ago
12

Which formula represents the law of conservation of energy?

Physics
1 answer:
Amiraneli [1.4K]3 years ago
4 0

Answer:

KE+PE

Explanation:

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What object did you choose to put on the skateboard ​
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Einstein and Lorentz, being avid tennis players, play a fast-paced game on a court where they stand 20.0 m from each other. Bein
kobusy [5.1K]

Answer:

Explanation:

a ) Kinetic energy of ball = 1/2 m v² , m is mass of the ball and v is its velocity

= 1/2 x .058 x 80²

= 185.6 J .

b ) The velocity of ball is very high so we shall find out the relativistic kinetic energy , the formula is given below

kinetic energy = mc² (    \frac{1}{\sqrt{1-\frac{v^2}{c^2} } } -1  )

= mc² x \frac{1}{\sqrt{1-\frac{v^2}{c^2} } }   - mc²

= .058 x 9 x 10¹⁶ x \frac{1}{\sqrt{1-\frac{1.8^2}{3^2} } }  - .058 x 9 x 10¹⁶

= .058 x 9 x 10¹⁶ x 1 / .8 - .058 x 9 x 10¹⁶

.058 x 9 x 10¹⁶ ( 1.25 - 1 )

= .058 x 9 x 10¹⁶ x .25

= .1305 x 10¹⁶

= 13.05 x 10¹⁴ J .

4 0
4 years ago
Please help with these questions ASAP. If correct I will give brainliest.
rusak2 [61]

answer

1)the direction is from the body of a high temperature to a body at a low temperature

2)at the melting point and boiling point because the heat given is used to break down the forces holding the particles together so that they can change their state

3)In a gas because the particles of gases are held by weak forces thus have large intermolecular spaces between the particles while the solids are in a fixed position

4)heat is transferred to another body if they experience different temperatures

7 0
3 years ago
A single-turn circular loop of wire of radius 5.0 cm lies in a plane perpendicular to a spatially uniform magnetic field. During
Artemon [7]

Answer:

Induced EMF,\epsilon=0.0143\ volts

Explanation:

Given that,

Radius of the circular loop, r = 5 cm = 0.05 m

Time, t = 0.0548 s

Initial magnetic field, B_i=200\ mT=0.2\ T

Final magnetic field, B_f=300\ mT=0.3\ T

The expression for the induced emf is given by :

\epsilon=\dfrac{d\phi}{dt}

\phi = magnetic flux

\epsilon=\dfrac{d(BA)}{dt}

\epsilon=A\dfrac{d(B)}{dt}

\epsilon=A\dfrac{B_f-B_i}{t}

\epsilon=\pi (0.05)^2\times \dfrac{0.3-0.2}{0.0548}

\epsilon=0.0143\ volts

So, the induced emf in the loop is 0.0143 volts. Hence, this is the required solution.

5 0
3 years ago
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