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stiks02 [169]
3 years ago
15

5. Describe the shape of the waveform in the secondary coil for a sine, square and triangle wave in the primary coil. How does t

he signal in the secondary coil relate to the one in the primary coil
Physics
1 answer:
Volgvan3 years ago
5 0

Answer:

When primary coil is exited by sin wave,this will result in sin wave in secondary coil as well.According to law,flux induced in the secondary coil will have same waveform as in the primary coil.

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Bill is learning to play tennis. He does pretty well hitting the ball back to his opponent but, many times he misses the ball wh
KiRa [710]

Answer: Place his feet parallel to the baseline prior to tossing the ball

5 0
2 years ago
What is the restoring force of a pendulum
salantis [7]

Answer:

the Restoring force causes the vibrating object to go slower going further from the equilibrium position and to go faster as it approaches the equilibrium position. the restoring force is what is causing the vibration The tension force comes from the string tugging on the bob of the pendulum.

Explanation:

3 0
3 years ago
How do altitude temperature and air pressure relate
kiruha [24]
They relate because the further up you go, the colder it gets, and the air pressure decreases the further up you go. The altitude temperature and the air pressure both decrease, and that is their relationship. Altitude temperature decreases, the higher you go, and air pressure also decreases, the higher up you go. Therefore, the lower down you go, the higher the air pressure, and the higher the altitude temperature.

Hope this helps and have a nice day:)
7 0
3 years ago
Read 2 more answers
Is hydrogen balloon element mixture or compound
andrezito [222]

Answer:

compound

Explanation:

5 0
2 years ago
In a "Rotor-ride" at a carnival, people rotate in a vertical cylindrically walled "room." If the room radius is 5.5 m, and the r
Crank

Answer:

0.181

Explanation:

We can convert the 0.5 rps into standard angular velocity unit rad/s knowing that each revolution is 2π:

ω = 0.5 rps = 0.5*2π = 3.14 rad/s

From here we can calculate the centripetal acceleration

a_c = \omega^2r = 3.14^2*5.5 = 54.3 m/s^2

Using Newton 2nd law we can calculate the centripetal force that pressing on the rider, as well as the reactive normal force:

F = N = a_cm = 54.3 m

Also the friction force and friction acceleration

F_f = N\mu = 54.3 m \mu N

a_f = F_f / m = 54.3 \mu

For the rider to not slide down, friction acceleration must win over gravitational acceleration g = 9.81 m/s2:

g = a_f = 54.3 \mu

9.81 = 54.3 \mu

\mu = 9.81 / 54.3 = 0.181

6 0
3 years ago
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