Correct answer id option C that is tropical.
Tropical Climate is characterized by constant high temperature at sea level with an average temperature of 18°C or higher and is found near the equator.
Areas with tropical climate have high humidity and temperature. Countries in tropical region have high precipitation rate. Tropical climate is also known as equatorial climate. Tropical regions are found near equator. Due to high convection rate, there is abundant rainfall.
Answer:
![\boxed {\boxed {\sf 100 \ Newtons}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%20100%20%5C%20Newtons%7D%7D)
Explanation:
We are asked to calculate the force you are applying to a car. According to Newton's Second Law of Motion, force is the product of mass and acceleration. Therefore, we can use the following formula to calculate force.
![F= m \times a](https://tex.z-dn.net/?f=F%3D%20m%20%5Ctimes%20a)
The mass of the car is 2000 kilograms and the acceleration is 0.5 meters per second squared.
Substitute the values into the formula.
![F= 2000 \ kg \times 0.05 \ m/s^2](https://tex.z-dn.net/?f=F%3D%202000%20%5C%20kg%20%5Ctimes%200.05%20%5C%20m%2Fs%5E2)
Multiply.
![F= 100 \ kg *m/s^2](https://tex.z-dn.net/?f=F%3D%20100%20%5C%20kg%20%2Am%2Fs%5E2)
Convert the units. 1 kilogram meter per second squared is equal to 1 Newton. Our answer of 100 kilogram meters per second square is equal to 100 Newtons.
![F= 100 \ N](https://tex.z-dn.net/?f=F%3D%20100%20%5C%20N)
You apply <u>100 Newtons</u> of force to the car.
It depends on the type of question, mechanical condition and given values,
You can use the formula,
Coefficient of static friction = Force of Static friction / Normal force (perpendicular to contacting surfaces)
Hope this helps!
The energy needed to vaporize 100 grams of ice at starting at 0°C is 300.83 kJ.
<h3>What is heating?</h3>
When the temperature is increased , the body or particle is said to be heating.
Given is the mass of water =100g =0.1 kg, Latent heat of fusion L = 333.7 kJ/kg,
Energy required to melt ice into water at 0°C.
Q₁ = mL
Q₁ = 0.1 x 333.7
Q₁ = 33.37 kJ
Energy required to heat water from 0°C to 100°C is
Q₂ = mCΔT
Q₂ = 0.1 x 4.186 x 100
Q₂ = 41.86 J
Energy required to vaporize at 100°C is
Q₃ = m Lv
Q₃ = 0.1 x 2256
Q₃ = 225.6 kJ
Total heat to vaporize 100 grams of ice at starting at 0°C is
Q = Q₁ +Q₂ +Q₃
Q = 33.37 +41.86 +225.6
Q = 300.83 kJ
Thus, the energy needed to vaporize 100 grams of ice at starting at 0°C is 300.83 kJ
Learn more about heating.
#SPJ1
I think it will go down like decrease minus or whatever you call it