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3 years ago

Please me with my math

Mathematics

2 answers:

Katyanochek1 [597]3 years ago

7 0

Answer:

8/9, $\sqrt{2}$ , 11/5, $\sqrt{9\\}$ , π, 11/3, 5

Step-by-step explanation:

Simplify and this should be the answer

Nady [450]3 years ago

7 0

$8/9, 2, 11/5, 9, pie, 11/3, 5$ Answer:

Step-by-step explanation:

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What is the greatest common factor of 36,12, and 45

Andreas93 [3]

Answer:

Step-by-step explanation:

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2 years ago

Eight children were in a ballet class. Three of them were wearing a pink leotard. What fraction of them did not have a pink leot

leva [86]

Answer:

5/8

Step-by-step explanation:

8 children in class

3 have pink on

8-3 = 5

That means 5 do not have pink

Fraction that do not have pink

those that do not have pink/total

5/8

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3 years ago

Write the fraction 15/25 in simplest form.if the fraction is in simplest form write simplified.

Elina [12.6K]

The simplest for of 15/25 is 3/5

6 0

3 years ago

Read 2 more answers

What is the discrimination of 3x^2+6x=2

Pavlova-9 [17]

60
D>0, there are 2 distinct real roots

Explanation:

3x2+6x−2=0
a=3,b=6,c=−2

The formula for discriminant is b2−4acSubstitute the given values.

b2−4ac
(6)2−4(3)(−2)
=60
therefore, D>0, there are 2 distinct real roots

8 0

3 years ago

Read 2 more answers

The number of people arriving for treatment at an emergency room can be modeled by a Poisson process with a rate parameter of si

OverLord2011 [107]

Answer:

a) P(x=3)=0.089

b) P(x≥3)=0.938

c) 1.5 arrivals

Step-by-step explanation:

Let t be the time (in hours), then random variable X is the number of people arriving for treatment at an emergency room.

The variable X is modeled by a Poisson process with a rate parameter of λ=6.

The probability of exactly k arrivals in a particular hour can be written as:

$P(x=k)=\lambda^{k} \cdot e^{-\lambda}/k!\\\\P(x=k)=6^k\cdot e^{-6}/k!$

a) The probability that exactly 3 arrivals occur during a particular hour is:

$P(x=3)=6^{3} \cdot e^{-6}/3!=216*0.0025/6=0.089\\\\$

b) The probability that <em>at least</em> 3 people arrive during a particular hour is:

$P(x\geq3)=1-[P(x=0)+P(x=1)+P(x=2)]\\\\\\P(0)=6^{0} \cdot e^{-6}/0!=1*0.0025/1=0.002\\\\P(1)=6^{1} \cdot e^{-6}/1!=6*0.0025/1=0.015\\\\P(2)=6^{2} \cdot e^{-6}/2!=36*0.0025/2=0.045\\\\\\P(x\geq3)=1-[0.002+0.015+0.045]=1-0.062=0.938$

c) In this case, t=0.25, so we recalculate the parameter as:

$\lambda =r\cdot t=6\;h^{-1}\cdot 0.25 h=1.5$

The expected value for a Poisson distribution is equal to its parameter λ, so in this case we expect 1.5 arrivals in a period of 15 minutes.

$E(x)=\lambda=1.5$

3 0

3 years ago