What is the approximate volume of the sphere

Solve: 2cos(x)-square root 3=0 for 0 less than x less than 2 pi

Leona [35]

Answer:

The general solution of $cos x = cos(\frac{\pi }{6})$ is

x = 2nπ± $\frac{\pi }{6}$

The general solution values

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

Step-by-step explanation:

Explanation:-

Given equation is

$2cosx-\sqrt{3} =0 for 0$

$2cosx =\sqrt{3}$

Dividing '2' on both sides, we get

$cos x =\frac{\sqrt{3} }{2}$

$cos x = cos(\frac{\pi }{6})$

General solution of cos θ = cos ∝ is θ = 2nπ±∝

Now The general solution of $cos x = cos(\frac{\pi }{6})$ is

x = 2nπ± $\frac{\pi }{6}$

put n=0

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

Put n=1

$x = 2\pi +\frac{\pi }{6} = \frac{13\pi }{6}$

$x = 2\pi -\frac{\pi }{6} = \frac{11\pi }{6}$

put n=2

$x = 4\pi +\frac{\pi }{6} = \frac{25\pi }{6}$

$x = 4\pi -\frac{\pi }{6} = \frac{23\pi }{6}$

And so on

But given 0 < x< 2π

The general solution values

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

6 0

2 years ago

It take Andre 4 minutes to swim 5 laps.

Liula [17]

Answer:

a. 1.25 laps per min

b. .8 min per lap

c. 17.6 minutes

Step-by-step explanation:

5 0

2 years ago

the temper ire of chicken soup is 192.7 F as it cools the temperature of the soup decreases 2.3 what is the temperature of the s

ad-work [718]

The temperature of soup after 25 minutes is $135.2^{\circ}\ F$

Solution:

The temperature of chicken soup is 192.7°F

As it cools, the temperature of the soup decreases 2.3°F per minute

Let the initial temperature be $T_0$

Let "t" be the time for rate of decrease

Set up an equation

Temperature = Initial temperature - decrease in temperature

Decrease in temperature = rate of decrease x time

Therefore,

$T = T_0-2.3t$

To find the temperature of soup after 25 minutes, substitute t = 25

$T = 192.7 - 2.3 (25)\\\\T = 192.7 -57.5\\\\T = 135.2$

Thus the temperature of soup after 25 minutes is $135.2^{\circ}\ F$

5 0

2 years ago

Can someone please help I’m trying to get my grades up it’ll be greatly appreciated

Veronika [31]

Answer:

A. 4

B. 8

Step-by-step explanation:

7 0

2 years ago

find the volume of cubical box . if the cost of painting of outer surface is rs 1440 at the rate rs 15 per mcube

bearhunter [10]

Surface of a cubical box=6(side²)

1)We have to calculate the surface of this cubical box.
Rate=cost of painting / surface ⇒surface=cost of painting/rate

Data:
Rate=$15/m²
cost of painting=$1440

Surface=$1440/($15/m²)=96 m²

2)We find out the length of the side:

Surface of a cubical box=6(side²)

Data:
Surface of a cubical box=96 m2

Therefore:
96m²=6 (side²)
side²=96 m²/6
side²=16 m²
side=√(16 m²)=4 m

3) We find the volume of a cubical box.
volume=(side³)
volume=(4 m)³
volume=64 m³

Answer: the volume of this cubical box would be 64 m³.

3 0

2 years ago