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bezimeni [28]
3 years ago
10

I need help, fast! I'll give brainliest whoever answers

Mathematics
1 answer:
MrMuchimi3 years ago
5 0

Answer:

k = -2j+24

Step-by-step explanation:

We have 2 points on the trend line

(4,16) and (6,12)

We can find the slope

m = (y2-y1)/(x2-x1)

   = (12-16)/(6-4)

   = -4/2

  = -2

The slope is -2

The y intercept is 24  (where it crosses the y axis)

Writing the equation in the form y= mx+b

k = -2j+24

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Solve each equation.<br> 1)<br> 9c + 1 = 10
Vinvika [58]

Answer:

doesnt c = 1

Step-by-step explanation:

I don't even know I'm just tryna get points

3 0
3 years ago
Find the value of s 1/4s+14=26
ValentinkaMS [17]
\dfrac{1}{4}s + 14 = 26

Take away 14 from both sides:

\dfrac{1}{4}s = 12

Multiply 4 on both sides :

s = 48
3 0
3 years ago
Read 2 more answers
State the value of the discriminant of 5x2 + 9x = 3.<br> please answer quick!
tekilochka [14]

Answer:

141

Step-by-step explanation:

convert to standard form then use D= B squared -4ac

3 0
3 years ago
A bow and arrow hunter walks toward the origin along the positive x-axis, with unit speed. At time 0, he is at x=10. His arrow (
Tamiku [17]

Answer:

Step-by-step explanation:

Complete question:

Vector Functions and Parametric Equations

A bow-and-arrow hunter walks toward the origin along the positive x-axis, with unit speed; at time 0 he is at x = 10. His arrow (of unit length) is aimed always toward a rabbit hopping with constant velocity √5 in the first quadrant along the line y = 2x; at time 0 it is at the origin.

a) Write down the vector function A(t) for the arrow at time t.

b) The hunter shoots (and misses) when closest to the rabbit; when is that?

Answer:

Attached

5 0
4 years ago
Which are the x-intercept and y-intercept of the line drawn through the points A and B?
ladessa [460]
First you have to figure out what the equation of the line is. Let's use the slope formula to find the slope, and then one of the points to find the y-intercept. We'll put the line's equation in y=mx+b form.

slope =  \frac{ y_{2} -  y_{1}  }{ x_{2} - x_{1}  } \\ slope = m \\ m =  \frac{5 - 1}{-7 - 1} \\ m =  \frac{4}{-8} \\ m = - \frac{1}{2}

Now, we'll use that slope in y=mx+b form with one of the coordinates in order to find what b (which is also the y-intercept) equals
y = - \frac{1}{2}x + b \\ 1 = 1(- \frac{1}{2}) + b \\ 1 = - \frac{1}{2} + b \\ 1 \frac{1}{2} = b

therefore your y-intercept is equal to 1.5. In order to find the x-intercept we'll take our new equation y = - \frac{1}{2} + 1 \frac{1}{2} and make y = 0, because the line intersects with the x-axis when y is equal to zero.

y = - \frac{1}{2}x + 1 \frac{1}{2} \\ 0 = - \frac{1}{2}x + 1 \frac{1}{2} \\ -1 \frac{1}{2} = - \frac{1}{2}x \\ x =  3

therefore, your x-intercept is 3 and your y-intercept is 1.5
6 0
3 years ago
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