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2 years ago

15

Answer Please! Will give Brainlist! 'Easy'

1 answer:

Nataly [62]2 years ago

6 0

Answer:

i think its 0.4x+7<1 I don't really know

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A roller coaster can give rides to 50 more people. Each car can hold 5 people. What is the best way to interpret the remainder o

kompoz [17]

My answer would be the letter B

7 0

2 years ago

It takes a turtle 3 ¼ hours to walk 1 ½ miles. How many hours does it take to walk one mile?

Norma-Jean [14]

Answer:

It will take 6/13 hours to walk one mile

Step-by-step explanation:

Here, we want to calculate the number of hours it take to walk one mile

From the question, 1 1/2 miles take 3 1/4 hours

the number of hours it will take to walk 1 mile will be;

1 1/2 divided by 3 1/4

= 3/2 divided by 13/4

= 3/2 * 4/13 = 6/13 hours

4 0

2 years ago

(x +y)^5<br> Complete the polynomial operation

Vesna [10]

Answer:

Please check the explanation!

Step-by-step explanation:

Given the polynomial

$\left(x+y\right)^5$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

$a=x,\:\:b=y$

$=\sum _{i=0}^5\binom{5}{i}x^{\left(5-i\right)}y^i$

so expanding summation

$=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5$

solving

$\frac{5!}{0!\left(5-0\right)!}x^5y^0$

$=1\cdot \frac{5!}{0!\left(5-0\right)!}x^5$

$=1\cdot \:1\cdot \:x^5$

$=x^5$

also solving

$=\frac{5!}{1!\left(5-1\right)!}x^4y$

$=\frac{5}{1!}x^4y$

$=\frac{5}{1!}x^4y$

$=\frac{5x^4y}{1}$

$=\frac{5x^4y}{1}$

$=5x^4y$

similarly, the result of the remaining terms can be solved such as

$\frac{5!}{2!\left(5-2\right)!}x^3y^2=10x^3y^2$

$\frac{5!}{3!\left(5-3\right)!}x^2y^3=10x^2y^3$

$\frac{5!}{4!\left(5-4\right)!}x^1y^4=5xy^4$

$\frac{5!}{5!\left(5-5\right)!}x^0y^5=y^5$

so substituting all the solved results in the expression

$=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5$

$=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$

Therefore,

$\left(x\:+y\right)^5=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$

6 0

2 years ago

Please help ...........

sammy [17]

Answer:

Angle B = 80°

see attachment......

7 0

2 years ago

It's easy math but I am not very good at it, I need some help. can someone help me????? solve all 3of them please!

jonny [76]

Answer:

1. 458 - 247 = 211

2. 58.92 - 43.87 = 15.05

3. 51/8 - 15/8 = 4.5

Here you go ! Hope this helps !

4 0

2 years ago

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