All categories

3 years ago

Solve for x. Please help quick, it’s my last question for my test

Mathematics

1 answer:

Sladkaya [172]3 years ago

3 0

Answer:

x = 9

Step-by-step explanation:

84 + (7x + 5) + (180 - (17x-1)) = 180

84 + 7x + 5 + (181 - 17x) = 180

270 + (-10x) = 180

90 = 10x

x = 9

You might be interested in

4|n|-5=7 please help me solve

DedPeter [7]

I think you meant to type

4(n)-5=7.

4n = 7 + 5

4n = 12

n = 12/4

n = 3

3 0

3 years ago

Read 2 more answers

In which quadrant do the points have negative x-coordinates and negative y-coordinates?

posledela

The answer is Quadrant III.

5 0

3 years ago

Read 2 more answers

Solve the proportional equation 3/r = 5/r+3

romanna [79]

Answer:

r=9/2 or 4.5

Step-by-step explanation:

First of all our goal is to get R by itself

by cross multiplying we get,

(r+3)*3=5r

by distributive property we get

3r+9=5r

substracting 3r from both sides we get

9=2r

by dividing by 2 in both sides we get

r=9/2 or 4.5

6 0

3 years ago

Show that y=cos(t)y=cos(t) is a solution to (dydt)2=1−y2(dydt)2=1−y2. Enter your answers below in terms of the independent varia

GrogVix [38]

Answer:

$(\frac{dy}{dt})^2=sin^2t$

Step-by-step explanation:

$y=cost$

DE : $(\frac{dy}{dt})^2=1-y^2$

If y is a solution of given DE then it satisfied the DE.

Differentiate w.r.t t

$\frac{dy}{dt}=-sint$

Using the formula

$\frac{d(cosx)}{dx}=-sinx$

LHS: $(\frac{dy}{dt})^2=(-sint)^2=sin^2t$

RHS

$1-y^2=1-cos^2t=sin^2t$

By using the formula

$sin^2t=1-cos^2t$

LHS=RHs

Hence, y is a solution of given DE

$(\frac{dy}{dt})^2=sin^2t$

7 0

3 years ago

X and y are both bigger than 30. x and y have HCF 21 and LCM 1617. Find x and y.

Sunny_sXe [5.5K]

The values of x and y are 99 and 343

The HCF of numbers is the highest common factors of the numbers

The LCM of numbers is the lowest common multiple of the numbers

The HCF and the LCM are given as:

$HCF = 21$

$LCM = 1617$

Multiply the HCF and the LCM

$HCF \times LCM = 21 \times 1617$

$HCF \times LCM = 33957$

The product of the numbers x and y equals the product of the HCF and the LCM.

So, we have:

$x \times y = 33957$

<h3>Prime Factors</h3>

Express 33957 as a prime factor

$x \times y = 3^2 \times 7^3 \times 11$

Rewrite the equation as

$x \times y = 99 \times 7^3$

$x \times y = 99 \times 343$

By comparison:

$x = 99$

$y= 343$

Hence, the values of x and y are 99 and 343