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2 years ago

Solve for x. Please help quick, it’s my last question for my test

Mathematics

1 answer:

Sladkaya [172]2 years ago

3 0

Answer:

x = 9

Step-by-step explanation:

84 + (7x + 5) + (180 - (17x-1)) = 180

84 + 7x + 5 + (181 - 17x) = 180

270 + (-10x) = 180

90 = 10x

x = 9

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A theme park had 1099 visitors in 3 days.There were twice as many visitors on saturday than on Friday.There were 234 more visito

Blababa [14]

Answer: there were 692 visitors on Saturday.

Step-by-step explanation:

Let x represent the number of visitors that were there on Friday.

Let y represent the number of visitors that were there on Saturday.

Let z represent the number of visitors that were there on Sunday.

The theme park had 1099 visitors in 3 days. It means that

x + y + z = 1099- - - - - - - - - - - - - -1

There were twice as many visitors on saturday than on Friday. This means that

y = 2x

x = y/2

There were 234 more visitors on Sunday than on Saturday. This means that

z = y + 234

Substituting x = y/2 and z = y + 234 into equation 1, it becomes

y/2 + y + y + 234 = 1099

Cross multiplying by 2, it becomes

y + 2y + 2y + 468 = 2198

5y = 2198 - 468

5y = 1730

x = 1730/5

x = 346

y = 2x = 2 × 346

y = 692

z = y + 234 = 692 + 234

z = 926

3 0

2 years ago

Match each transformations to the shape it maps shape 1 onto ... Drag the tiles to correct boxes to complete the pairs

rosijanka [135]

Answer:

shape V -----> 90° counterclockwise

shape II ------> 90° clockwise

shape III -----> translation

shape IV -----> 180° rotation

7 0

2 years ago

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A custom t-shirt company charges a $200 setup fee and $5 per t-shirt. Write an equation that can be used to determine how many t

SashulF [63]

A. (200+5x)/x =5.33 I think I don’t know

3 0

2 years ago

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Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.

MrMuchimi

A random variable following a binomial distribution over $n$ trials with success probability $p$ has PMF

$f_X(x)=\dbinom nxp^x(1-p)^{n-x}$

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

$\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1$

The mean is given by the expected value of the distribution,

$\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}$

The remaining sum has a summand which is the PMF of yet another binomial distribution with $n-1$ trials and the same success probability, so the sum is 1 and you're left with

$\mathbb E(x)=np=126\times0.27=34.02$

You can similarly derive the variance by computing $\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$ , but I'll leave that as an exercise for you. You would find that $\mathbb V(X)=np(1-p)$ , so the variance here would be

$\mathbb V(X)=125\times0.27\times0.73=24.8346$

The standard deviation is just the square root of the variance, which is

$\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834$

7 0

3 years ago

What type of transformation is shown?

Blizzard [7]

Translation is shown.

3 0

3 years ago

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