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blagie [28]
3 years ago
14

Solve for x. Please help quick, it’s my last question for my test

Mathematics
1 answer:
Sladkaya [172]3 years ago
3 0

Answer:

x = 9

Step-by-step explanation:

84 + (7x + 5) + (180 - (17x-1)) = 180

84 + 7x + 5 + (181 - 17x) = 180

270 + (-10x) = 180

90 = 10x

x = 9

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4|n|-5=7 please help me solve
DedPeter [7]
I think you meant to type

4(n)-5=7.

4n = 7 + 5

4n = 12

n = 12/4

n = 3
3 0
3 years ago
Read 2 more answers
In which quadrant do the points have negative x-coordinates and negative y-coordinates?
posledela
The answer is Quadrant III.
5 0
3 years ago
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Solve the proportional equation 3/r = 5/r+3
romanna [79]

Answer:

r=9/2 or 4.5

Step-by-step explanation:

First of all our goal is to get R by itself

by cross multiplying we get,

(r+3)*3=5r

by distributive property we get

3r+9=5r

substracting 3r from both sides we get

9=2r

by dividing by 2 in both sides we get

r=9/2 or 4.5

6 0
3 years ago
Show that y=cos(t)y=cos(t) is a solution to (dydt)2=1−y2(dydt)2=1−y2. Enter your answers below in terms of the independent varia
GrogVix [38]

Answer:

(\frac{dy}{dt})^2=sin^2t

Step-by-step explanation:

y=cost

DE :(\frac{dy}{dt})^2=1-y^2

If y is a solution of given DE then it satisfied the DE.

Differentiate w.r.t t

\frac{dy}{dt}=-sint

Using the formula

\frac{d(cosx)}{dx}=-sinx

LHS:(\frac{dy}{dt})^2=(-sint)^2=sin^2t

RHS

1-y^2=1-cos^2t=sin^2t

By using the formula

sin^2t=1-cos^2t

LHS=RHs

Hence, y is a solution of given DE

(\frac{dy}{dt})^2=sin^2t

7 0
3 years ago
X and y are both bigger than 30. x and y have HCF 21 and LCM 1617. Find x and y.
Sunny_sXe [5.5K]

The values of x and y are 99 and 343

<h3>The HCF</h3>

The HCF of numbers is the highest common factors of the numbers

<h3>The LCM</h3>

The LCM of numbers is the lowest common multiple of the numbers

The HCF and the LCM are given as:

HCF = 21

LCM = 1617

Multiply the HCF and the LCM

HCF \times LCM = 21 \times 1617

HCF \times LCM = 33957

The product of the numbers x and y equals the product of the HCF and the LCM.

So, we have:

x \times y = 33957

<h3>Prime Factors</h3>

Express 33957 as a prime factor

x \times y = 3^2 \times 7^3 \times 11

Rewrite the equation as

x \times y = 99 \times 7^3

x \times y = 99 \times 343

By comparison:

x = 99

y= 343

Hence, the values of x and y are 99 and 343

Read more about HCF and LCM at:

brainly.com/question/420337

6 0
2 years ago
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