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3 years ago

20 yards 8 inches is divided into 26 equal sections, how long is each section

1 answer:

5 0

In the given question, there are several information's of immense importance and worth taking a look. based on these information's, the answer to the question can be easily determined.The length that has to be divided into 26 equal parts is 20 yards and 8 inches.Firstly we have to change the yard into inches and then we can divide the total inches into 26 equal parts.
We know
1 yard = 36 inches
20 yards = 720 inches
Then the total length that has to be divided = (720 + 8) inches
= 728 inches
Now we have to divide the 728 inches into 26 equal parts.
Length of each section = (728/26) inches
= 28 inches.
So each of the 26 parts will have a length of 28 inches.

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A school wants to buy a chalkboard that measures 3 feet by 4 feet the chalkboard cost $6.14 per square foot. How much will the c

ElenaW [278]

Answer:

$49.12

Step-by-step explanation:

8 0

3 years ago

Which system of inequalities represents reglon Z?<br> 6

yKpoI14uk [10]

Answer:

The system of inequalities is

y\geq 3x-2

y<-(1/5)x+2

Step-by-step explanation:

step 1

Find the equation of the solid blue line

Let

A(0,-2), B(1,1)

Find the slope of AB

m=(1+2)/(1-0)=3

The equation of the line into slope intercept form is equal to

y=mx+b

we have

m=3

b=-2 - ----> the point A is the y-intercept

substitute

y=3x-2 - -----> equation of the solid blue line

The solution of the inequality is the shaded area above the solid line

therefore

The first inequality is

y\geq 3x-2

C(0,2), D(5,1)

step 2

Find the equation of the dashed red line

Let

Find the slope of CD

m=(1-2)/(5-0)=-1/5

The equation of the line into slope intercept form is equal to

y=mx+b

we have

m=-1/5

b=2 ----> the point C is the y-intercept

substitute

y=-(1/5)x+2 -----> equation of the dashed red line

The solution of the inequality is the shaded area below the dashed line

therefore

The second inequality is

y<-(1/5)x+2

The system of inequalities is

y\geq 3x-2

y<-(1/5)x+2

3 0

3 years ago

Find the product and simplify. (3c-5) ^2

RSB [31]

Answer:

9c² -30c + 25

Step-by-step explanation:

Perfect square trinomial: (a - b)² = a² - 2ab + b²

(3c - 5)²

(3c)² -2(3c * 5) + 5²

9c² -2(15c) + 5²

9c² -30c + 25

Final answer: 9c² -30c + 25

Hope this helps!

7 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B

inysia [295]

$\large \bigstar \frak{ } \large\underline{\sf{Solution-}}$

Consider, LHS

$\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} \\ \\ \text{So, using this identity, we get} \\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered} \\$

So, using this identity, we get

$\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

can be rewritten as

$\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}$

<h2>Hence,</h2>

$\begin{gathered} \\ \rm\implies \:\boxed{\sf{ \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}$

$\rule{190pt}{2pt}$

5 0

2 years ago

The height of a triangle is 8 cm more than the base. If the area is 24 cm2, find the height and base of the triangle.

Elden [556K]

Answer:

height = 12 cm

base length = 4 cm

Step-by-step explanation:

area of a triangle

base length × height / 2

x = height

y = base length

x = y + 8

24 = y × (y + 8) / 2

48 = y × (y + 8) = y² + 8y

squared equation

y² + 8y - 48 = 0

solution

y = (-b ± sqrt(b² - 4ac))/(2a)

a = 1

b = 8

c = -48

y = (-8 ± sqrt(64 - 4×-48))/2 = (-8 ± sqrt(64 + 192))/2 =

= (-8 ± sqrt(256))/2 = (-8 ± 16)/2 = -4 ± 8

y1 = -4 + 8 = 4 cm

y2 = -4 - 8 = -12

but a negative base length did not make any sense, so only y = 4 remains.

x = y + 8 = 4 + 8 = 12 cm

5 0

3 years ago