Answer:
1.25 liters of oil
Step-by-step explanation:
Volume in Beaker A = 1 L
Volume of Oil in Beaker A = 1*0.3 = 0.3 L
Volume of Vinegar in Beaker A = 1*0.7 = 0.7 L
Volume in Beaker B = 2 L
Volume of Oil in Beaker B = 2*0.4 = 0.8 L
Volume of Vinegar in Beaker B = 1*0.6 = 1.2 L
If half of the contents of B are poured into A and assuming a homogeneous mixture, the new volumes of oil (Voa) and vinegar (Vva) in beaker A are:

The amount of oil needed to be added to beaker A in order to produce a mixture which is 60 percent oil (Vomix) is given by:

1.25 liters of oil are needed.
The answer would be 6w^5y^3
That's 4! (faculty), ie., 4x3x2x1 = 24.
one of four can win, then there are 3 left for second place, and so on...
Let's solve your equation step-by-step.
x
=
0.25
x
Step 1: Subtract 0.25x from both sides.
x
−
0.25
x
=
0.25
x
−
0.25
x
0.75
x
=
0
Step 2: Divide both sides by 0.75.
0.75
x
0.75
=
0
0.75
x
=
0
Answer:
x
=
0