Answer:324
Step-by-step explanation:
int i = 42.7; /* konwersja z double do int */
float f = i; /* konwersja z int do float */
double d = f; /* konwersja z float do double */
unsigned u = i; /* konwersja z int do unsigned int */
f = 4.2; /* konwersja z double do float */
i = d; /* konwersja z double do int */
char *str = "foo"; /* konwersja z const char* do char* [1] */
const char *cstr = str; /* konwersja z char* do const char* */
void *ptr = str; /* konwersja z char* do void* */
Podcza
Answer: 907.92 ft²
Step-by-step explanation:
1. To solve this problem you must apply the formula for calculate the area of a circle, which is shown below:
Where r is the radius of the circle.
2. You know the radius of the circle B, therefore, when you susbtitute it into the formula, you obtain that the area of the circle B is:
Volume = 1/3a^2h
v= 1/3 x 8.2^2 x 5.3
v=118.79066666667 in^3
Answer:
59.15 in^2
Step-by-step explanation:
Using Heron's formula
semiperimeter , s = 1/2 ( 28.8+18+12) = 29.4
Area = sqrt ( 29.4(29.4-28.8)(29.4-18)(29.4-12) ) = 59.15 in^2
