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inna [77]
3 years ago
6

Please help I think I picked the wrong answer !!

Mathematics
1 answer:
insens350 [35]3 years ago
6 0

Answer:

one solution

Step-by-step explanation:

it has one solution because the slopes of the two equations(1x & 2x) are different, which means the lines of the two equations are not parallel, they have an intersection point(also means one solution).

You might be interested in
What is the best approximation of the surface area of this right cone
Tatiana [17]
Use the formula for the surface area of a right cone:

\sf A=\pi rs+\pi r^2

Where 'r' is the radius and 's' is the slant height, plug in what we know(use 3.14 to approximate for pi):

\sf A=(3.14)(12)(15)+(3.14)(12)^2

Multiply and simplify exponent:

\sf A=565.2+(3.14)(144)

Multiply:

\sf A=565.2+452.16

Add, round to the nearest whole number:

\boxed{\sf A\approx 1017~cm^2}
4 0
3 years ago
I need help with this problem. Given: BC = 10 inches AC = √50 inches m∠CBD = 60° m∠CAD = 90° Calculate the exact area of the sha
Nikitich [7]

Answer:

Area of the shaded region = 23.33 in²

Step-by-step explanation:

Area of a sector = \frac{\theta}{360}(\pi r^{2})

Where θ = Central angle subtended by an arc

r = radius of the circle

Area of the sector BCD = \frac{60}{360}(\pi) (10^{2})

                                       = 52.36 in²

Area of equilateral triangle BCD = \frac{\sqrt{3} }{4}(\text{Side})^2

                                                      = \frac{\sqrt{3} }{4}(10)^2

                                                      = 25\sqrt{3} in²

                                                      = 43.30 in²

Area of the shaded portion in ΔBCD = 52.36 - 43.3

                                                             = 9.06 in²

Area of sector CAD = \frac{90}{360}(\pi)(\sqrt{50})^2

                                 = 39.27 in²

Area of right triangle CAD = \frac{1}{2}(\text{Base})(\text{Height})

                                            = \frac{1}{2}(\text{AC})(\text{AD})

                                            = \frac{1}{2}(\sqrt{50})(\sqrt{50})

                                            = 25 in²

Area of the shaded part in the ΔACD = 39.27 - 25

                                                                         = 14.27 in²

Area of the shaded part of the figure = 9.06 + 14.27

                                                                = 23.33 in²

8 0
3 years ago
Please help, would be greatful :)
Ierofanga [76]

Answer:

16.9

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Is this function linear or nonlinear?​
Alekssandra [29.7K]

Answer:

yes

Step-by-step explanation:

3 0
3 years ago
-12 = 4x + 1<br> solve<br> algebra
Eddi Din [679]

Answer:

x=-\frac{13}{4}

Step-by-step explanation:

-12=4x+1\\4x=-12-1\\x=-\frac{13}{4}

4 0
3 years ago
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