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3 years ago

How much money is one third of $2.34

Mathematics

2 answers:

SCORPION-xisa [38]3 years ago

8 0

Divide it by 3.
$2.34 divided by 3.

BabaBlast [244]3 years ago

6 0

Answer:

$0.78 or 78 cents.

Step-by-step explanation:

We have to calculate one third of the money $2.34.

First we will rewrite the question as :

$\frac{1}{3}$ of 2.34

= $\frac{1}{3}$ × 2.34

= $0.78

Convert it into cents

1 dollar = 100 cents

0.78 dollar = 100 × 0.78

= 78 cents

One third of $2.34 is $0.78 or 78 cents.

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A circle has a radius of 3it has an arc with a 20 degree central angle

alexandr402 [8]

Answer:

Step-by-step explanation:

The circumference of the circle is 6π inches

The length of the arc is (20/360)×6π = 1.04 inches

(The complete circumference would cover 360°. Angle ALB is 20°)

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3 years ago

1 point) Use Stoke's Theorem to evaluate ∫CF⋅dr∫CF⋅dr where F(x,y,z)=xi+yj+1(x2+y2)kF(x,y,z)=xi+yj+1(x2+y2)k and CC is the bound

Drupady [299]

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Step-by-step explanation:

Thinking process:

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3 years ago

Solve for r and t: 6r - 3t = 6 6r + 8t = -16

MAVERICK [17]

Multiply the first equation with (-1)
you should get this

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start to eliminate

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8 0

3 years ago

SIMPLIFY THE EXPRESSION. 9(1 - 7x)

jok3333 [9.3K]

Answer:

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Step-by-step explanation:

9(1-7x)

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7 0

3 years ago

Read 2 more answers

5. The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero.

s2008m [1.1K]

Implementating the given algorithm in python 3, the greatest common divisors of (124 and 244) and (4424 and 2111) are 4 and 1 respectively.

The program implementation is given below and the output of the sample run is attached.

def gcd(a, b):

#initialize a function named gcd which takes in two parameters

if a>b:

#checks if a is greater than b

return gcd (b, a)

#if true interchange the Parameters and Recall the function

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

#even numbers leave no remainder when divided by 2, checks if a and b are even

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

#checks if a is odd and B is even

return gcd(a, b/2)

else :

return gcd(a, b-a)

#since it's a recursive function, it recalls the function with new parameters until a certain condition is satisfied

print(gcd(124, 244))

print()

#leaves a space after the first output

print(gcd(4424, 2111))

Learn more :brainly.com/question/25506437

6 0

3 years ago