Where's the graph?? I can't answer if there's no graph. lol xD
One formula for the lateral area is
A = 2(LW + H(L+W))
Filling in the given numbers, you have ...
A = 2((5.6 in)·(4.3 in) + (10 in)·(5.6 in + 4.3 in))
= 2(24.08 in² + 99 in²)
= 246.16 in²
Answer:
ℝ - {(-2/3),(3/2)}
Step-by-step explanation:
We want the domain of f(g(x)). So, firstly, we have to find the domain for g(x) and, then, for f(g(x)).
- Domain of g(x): Since the expression is a fracion, we must exclude the values of x that make null the denominator. Hence,

- Domain of f(g(x)): We'll find its expression:

Now, once again, we have to exclude the values of x that make the denominator equals to zero. Thus,

Lastly, we may write the domanin of f(g(x)):
![D(f(g(x)) = \left]-\infty,-\dfrac{2}{3}\right[\cup\left]-\dfrac{2}{3},\dfrac{3}{2}\right[\cup\left]\dfrac{3}{2},\infty\right[](https://tex.z-dn.net/?f=D%28f%28g%28x%29%29%20%3D%20%5Cleft%5D-%5Cinfty%2C-%5Cdfrac%7B2%7D%7B3%7D%5Cright%5B%5Ccup%5Cleft%5D-%5Cdfrac%7B2%7D%7B3%7D%2C%5Cdfrac%7B3%7D%7B2%7D%5Cright%5B%5Ccup%5Cleft%5D%5Cdfrac%7B3%7D%7B2%7D%2C%5Cinfty%5Cright%5B)
or, just writing in a shorter way:

The answer to #11 is: x = 15
The answer to #12 is: x = 5
105° can be expressed as 60°+45°. What we have then is sin(60°+45°). The sum pattern for sin is sin(a)cos(b)+cos(a)sin(b). We will fill in as follows: sin(60)c0s(45)+cos(60)sin(45). Now draw those special right triangles in the first quadrant to get the exact values for each. The sin of 60 is

, the cos of 45 is

, the cos of 60 is 1/2, and the sin of 45 is

. When we put all that together we get

. Simplifying all of that we have

. We can put that over the common denominator that is already there and get

. Not sure if that's simplified enough; you may be at the point in class where you are rationalizing your denominator, but I'm not sure, and if you're not, I don't want to confuse you.