Answer:
Therefore they are 734.106 miles apart.
Step-by-step explanation:
Given that ,
Two ships have a harbor together. The angle between two ships is 135°40'. Each of two ships travel 402 miles.
It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.
Let ∠B= 135°40', and AB = 402 miles , BC = 402 miles
Then the distance between the ships = AC
We know
The sum of all angles = 180°
⇒∠A+∠B+∠C=180°
⇒∠A+135°40'+∠C=180°
⇒2∠A= 180°- 135°40' [ since ∠A=∠C]
⇒2∠A=44°60'
⇒∠A= 22°30'
Again we know that,

Taking last two ratio,

Putting the value of BC , AC ,∠A,∠B


≈734.106 miles
Therefore they are 734.106 miles apart.
Answer:a
Step-by-step explanation:
h(x)=x-12
h(x)=4x-48
h(x)=-1(4x-48)
h(x)=-4x+48
h(x)=48-4x
The answer is X= 5. Using the pythagorean theorem, and assuming that "b" is 3, half of 6 because the triangle is isosceles, you can solve the problem.
Answer:
18 meters
Step-by-step explanation:
4 cm = 6m
2cm = 3m
6x3=18
Please <3 my Answer B )