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puteri [66]
3 years ago
15

Simplify the following expression (X9 Y5) -4

Mathematics
2 answers:
Lelechka [254]3 years ago
6 0

9. 5
The answer is X. Y. -4
KATRIN_1 [288]3 years ago
3 0

Answer:

Step-by-step explanation:

( x^{9} y^{5} )^{-4} \\x^{(9)(-4)} y^{(5)(-4)} \\x^{-36}y^{-20} \\\frac{1}{x^{36}y^{20}}

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Alex777 [14]

Answer:

m = -1/3

Step-by-step explanation:

There are two ways that you can use to get this answer.

The first way is to use the graph. You can see that to get from Point A to Point B, the dots go over 1 and down 3. For the fraction, you put the amount that you go to the side (1) over the amount you go down (3) to get 1/3. Since the points go down gradually, the slope is negative, so 1/3 becomes -1/3.

The second way is to take the two points, (1, 4) and (2, 1) and subtract them. First, subtract the x-coordinate from Point B from Point A to get -1. Then do the same thing with the y-coordinates to get 3. Put the -1 over 3 because x comes before y, and you have your slope.

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3 years ago
Drag the point A to the location indicated in each scenario to complete each statement.
Art [367]

The graph from which the position of the point <em>A</em> can determined following

the multiplication with a scalar is attached.

Responses:

  • If <em>A</em> is in quadrant I and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant III</u>
  • If A is in quadrant II and is multiplied by a positive scalar, <em>c</em>, then c·A is in <u>quadrant II</u>
  • If <em>A</em> is in quadrant II and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant IV</u>
  • If <em>A</em> is in quadrant III and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant I</u>

<h3>Methods by which the above responses are obtained</h3>

Background information;

The question relates to the coordinate system with the abscissa represent the real number and the ordinate representing the imaginary number.

Solution:

If A is in quadrant I; A = a + b·i

When multiplied by a negative scalar, <em>c</em>, we get;

c·A = c·a + c·b·i

Therefore;

c·a is negative

c·b is negative

  • c·A = c·a + c·b·i is in the <u>quadrant III</u> (third quadrant)

If A is quadrant II, we have;

A = -a + b·i

When multiplied by a positive scalar <em>c</em>, we have;

c·A = c·(-a) + c·b·i = -c·a + c·b·i

-c·a is negative

c·b·i is positive

Therefore;

  • c·A = -c·a + c·b·i is in <u>quadrant II</u>

Multiplying <em>A</em> by negative scalar if <em>A</em> is in quadrant II, we have;

c·A = -c·a + c·b·i

-c·a is positive

c·b·i is negative

Therefore;

c·A = -c·a + c·b·i is in <u>quadrant IV</u>

If A is in quadrant III, we have;

A = a + b·i

a is negative

b is negative

Multiplying <em>A</em> with a negative scalar <em>c</em> gives;

c·A = c·a + c·b·i

c·a is positive

c·b  is positive

Therefore;

  • c·A = c·a + c·b·i is in<u> quadrant I</u>

Learn more about real and imaginary numbers here;

brainly.com/question/5082885

brainly.com/question/13573157

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atroni [7]

Answer:

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Step-by-step explanation:

using point slope form.

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3 years ago
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timofeeve [1]
44x65=2860 is the answer
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3 years ago
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