Answer:
see below
Step-by-step explanation:
<em>Which of the equations from part A represent adding two rational numbers?</em>
Equations A, C, E
<em>What hypothesis can you make about the sum of two rational numbers?</em>
The sum of two rationals will always be rational
<em>Will the addition result in a rational or an irrational number?</em>
Our hypothesis is that the result is always rational. This can be justified by the fact that the sum of two rationals a/b + c/d, where a, b, c, d are integers and bd≠0, is (ad+bc)/(bd), a rational, based on closure of integers for multiplication and addition.
<em>Which equations represent the sum of a rational and an irrational number?</em>
Equations B, F
<em>What hypothesis can you make about the sum of an irrational and a rational number?</em>
The sum of a rational and irrational number is always irrational.
Okay so what we know is that there are 6 sides.
—————-————————————————————
3separate groups have the same measurements. So really 3 groups of 2 that have the same measurements.
—————————————————————
2 sides are 3*2 —————>an area of 6
2 sides are 3*2—————>an area of 6
2 sides are 2*2—————>an area of 4
—————————————————————so, we add those #s up and get 6+6+4 which equals 16 as your answer.
Answer:
f = -14
Step-by-step explanation:
given:
4 − (–5f) = –66
4 + 5f = -66 ( subtract 4 from both sides)
5f = -66 - 4
5f = -70 (divide both sides by 5)
f = (-70) / 5
f = -14
Answer:
ok i answer
Step-by-step explanation:
yes
