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zalisa [80]
3 years ago
14

A box is designed to hold pencils the front of the box will be made of a clear material for display. The rest of the box will be

made from cardboard
Mathematics
1 answer:
stellarik [79]3 years ago
5 0

Answer:

100 cm²

Step-by-step explanation:

Given that :

Length of prism = 20 cm

Height, h = 5cm

Width, w = 4 cm

The surface are of the side with clear material can be obtained by calculating the area of rectangule (front)

Area of rectangle = Length * height

Area = 20 * 5 = 100 cm²

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HELP PLEASE CAN’T FIGURE THIS OUT NEED HELP
Ivanshal [37]

Answer:

LN= 68°

Step-by-step explanation:

6 0
3 years ago
Two pumps connected in parallel fail independently of one another on any given day. The probability that only the older pump wil
Bogdan [553]

Answer : Probability that the pumping system will fail on any given day = 0.005

Explanation:

Probability that only older pump fail = P(A) = 0.10

Probability that only newer pump fail = P(B) = 0.05

Since they are independent events ,

then the conditions will be

P(A∩B) = P(A). P(B)

             = 0.10 ×0.05

             =  0.005

Hence, the probability will fail on any given day = 0.005

8 0
3 years ago
OLLEGE
Sophie [7]

<u>Part 1</u>

<u />(f\circ g)(x)=f(\sqrt{x})=4\sqrt{x}+1

We need to make sure the radical is defined, meaning the radicand has to be non-negative. Thus, the domain is \boxed{[0, \infty)}

<u>Part 2</u>

<u />(g \circ f)(x)=g(4x+1)=\sqrt{4x+1}

We need to make sure the radical is defined, meaning the radicand has to be non-negative. Thus,

4x+1 \geq 0\\\\4x \geq -1\\\\x \geq -\frac{1}{4}

Thus, the domain in interval notation is \boxed{\left[-\frac{1}{4}, \infty)}

8 0
2 years ago
The diagonal of a square is 27 cm long. The diagonal of a smaller square is 12 cm long. What is the difference between the lengt
kykrilka [37]

length of big square

\sqrt{27}  = 5.2

length of small square

\sqrt{12 }  = 3.5

difference between length of two square

=5.2-3.5

=1.7

7 0
3 years ago
How do you do this. Please give a full answer and explain why.
OverLord2011 [107]

<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u>

\displaystyle \large{ {a}^{ - n}  =  \frac{1}{ {a}^{n} } }

Compare the terms.

\displaystyle \large{ {a}^{ - n}  =   {( - 2)}^{ - 3} }

Therefore, a = -2 and n = 3. From the law of exponent above, we receive:

\displaystyle \large{ {( - 2)}^{ - 3}  =  \frac{1}{ {( - 2)}^{ 3} } }

<u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>D</u><u>e</u><u>f</u><u>.</u> (For cubic)

\displaystyle \large{ {a}^{3}  = a \times a \times a }

Factor (-2)^3 out.

\displaystyle \large{ {( - 2)}^{ - 3}  =  \frac{1}{( - 2) \times ( - 2) \times ( - 2)}}

(-2) • (-2) = 4 | Negative × Negative = Positive.

\displaystyle \large{ {( - 2)}^{ - 3}  =  \frac{1}{4 \times ( - 2)}}

4 • (-2) = -8 | Negative Multiply Positive = Negative.

\displaystyle \large{ {( - 2)}^{ - 3}  =  \frac{1}{  - 8}}

If either denominator or numerator is in negative, it is the best to write in the middle or between numerator and denominators.

Hence,

\displaystyle \large \boxed{ {( - 2)}^{ - 3}  =  -  \frac{1}{  8}}

The answer is - 1 / 8

3 0
3 years ago
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