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iogann1982 [59]
2 years ago
11

What is the solution to the equation below. square root x - 4 = -2

Mathematics
2 answers:
ArbitrLikvidat [17]2 years ago
8 0

Answer:

The answer is b.

Step-by-step explanation:

x-4=-2

+4. +4

x= 2

natita [175]2 years ago
3 0

Answer:

Answer A is correct

Step-by-step explanation:

√x - 4 = -2

√x = -2 + 4

√x = +2

x = 2²

x = 2 × 2

x = 4

 Hope this helps you :-)

Let me know if you have any other questions :-)

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Lolita deposited 500 in her savings account that earns 5% intrest compounded anually. She forgot about it until now, 15 years la
Sonja [21]

Answer:

P = 1039.5

Step-by-step explanation:

Given:-

- The initial amount deposited, Po = 500

- The interest rate applied, I = 5% compounded annually

Find:-

- The amount on her bank statement after 15 years?

Solution:-

- We see that the principal amount increases every year and no transactions have been made in the course of 15 years.

The total amount left in her savings account would be given by the following formula:

                         P = Po * ( 1 + I/100 )^n

- Where, n = number of years passed since deposit. (15 years)

                        P = 500 * ( 1 + 5/100 )^15

                        P = 500 * (1.05)^15

                        P = 1039.5  

6 0
2 years ago
Need answers as soon as possible, will give brainiest and rate 5/5.
aliya0001 [1]
1. x/-3=-15
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2. -7+3(-12)÷-3
-7+12
5

3. f(-4)=(-4)²-(-4)
f(-4)=16-(-4)
f(-4)=20

4. x-9=17

5. 2x+3=35

6. -8-12-(-20)
-20-(-20)
0

7. -2(-3)²(-1)
-2(9)(-1)
-18(-1)
18

8. x-(-2)

9. subtract 7 then divide by -2

10. 6+(-18)+(-13)+9
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11. 5x=11

12. division property

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3 years ago
Read 2 more answers
Find the oth term of the geometric sequence 7, 14, 28, ...
yaroslaw [1]

Answer:

The nth term of the geometric sequence 7, 14, 28, ... is:

a_n=7\cdot \:2^{n-1}

Step-by-step explanation:

Given the geometric sequence

7, 14, 28, ...

We know that a geometric sequence has a constant ratio 'r' and is defined by

a_n=a_1\cdot r^{n-1}

where a₁ is the first term and r is the common ratio

Computing the ratios of all the adjacent terms

\frac{14}{7}=2,\:\quad \frac{28}{14}=2

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now substituting r = 2 and a₁ = 7 in the nth term

a_n=a_1\cdot r^{n-1}

a_n=7\cdot \:2^{n-1}

Therefore, the nth term of the geometric sequence 7, 14, 28, ... is:

a_n=7\cdot \:2^{n-1}

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