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guapka [62]
2 years ago
6

X is proportional to root y where y>0

Mathematics
1 answer:
Ronch [10]2 years ago
6 0

Answer:

x is proportional to √y where y > 0

Step-by-step explanation:

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5 0
3 years ago
Put them in order smallest to largest:<br> 1.32,1.23,1.03,3.21,3.12
dlinn [17]

Answer:

1.03,  1.23,  1.32  3.12,  3.21

4 0
3 years ago
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Find a a pair of numbers of both 4y-4x=48 and y= x-11
stich3 [128]

Answer:

There is no solution because the slopes of the line are the same.

Step-by-step explanation:

4y - 4x = 48

    + 4x    + 4x        Add 4x to both sides

4y = 4x + 48          Divide both sides by 4

y = x + 12

Now set both equations equal to each other since they equal y

x + 12 = x - 11

-x         - x           Subtract x from both sides

12 ≠ -11                No Solution

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4 0
3 years ago
What are the endpoint coordinates for the midsegment of △BCD that is parallel to BC?
natulia [17]

Answer:

<em>The endpoint coordinates for the mid-segment are:  (-2,-1) and (1,0)</em>

Step-by-step explanation:

According to the given diagram, the coordinates of the vertices of \triangle BCD are:   B(-3,1), C(3,3) and D(-1,-3)

Now, the endpoints of the mid-segment of \triangle BCD which is parallel to BC will be the mid-points of sides BD and CD.

<u>Formula for the coordinate of mid-point</u> :   (\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}), where (x_{1}, y_{1}) and (x_{2}, y_{2}) are two endpoints.

So, the mid-point of BD will be:  (\frac{-3-1}{2},\frac{1-3}{2})=(\frac{-4}{2},\frac{-2}{2})=(-2,-1)

and the mid-point of CD will be:  (\frac{3-1}{2},\frac{3-3}{2})=(\frac{2}{2},\frac{0}{2})=(1,0)

Thus, the endpoint coordinates for the mid-segment of \triangle BCD that is parallel to BC are  (-2,-1) and (1,0)

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3 years ago
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irakobra [83]
The answer is D 2n-11
3 0
2 years ago
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