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2 years ago

Select the best equation needed to solve for x; then solve for x.

Mathematics

2 answers:

Alexandra [31]2 years ago

5 0

The answer is c. The answer is c because x=27
5*27+12=147

charle [14.2K]2 years ago

5 0

It is definitely c beacause if you take it step by step through the process that is what you get

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Need help with this question 15 (1 1/5)

lana [24]

$15\left(1\dfrac{1}{5}\right)=15\cdot\dfrac{1\cdot5+1}{5}=15\cdot\dfrac{6}{5}\\\\=3\cdot6=\boxed{18}$

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3 years ago

Find the value of x. Round the length to nearest tenth.

Lady_Fox [76]

From the law of sines, we have

$l = h\sin(\theta) = h\cos(\alpha)$

where $l$ is the leg we're interested in, $h$ is the hypothenuse, $\theta$ is the angle opposite to $l$ , and $\alpha$ is the angle between $l$ and $h$ .

So, in the first case, we can use

$x = 15\sin(35) \approx 8.6$

And in the second excercise, we use

$x = 11\cos(44) \approx 7.6$

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3 years ago

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Grandma received 0.25 liters of medicine from her doctor. The directions asked her to take one teaspoonful 3 times daily until i

kupik [55]

Answer:

Dec 10

Step-by-step explanation:

0.25 liter = 250 ml

4 ml * 3 = 12 ml

250/12 = 20.83 days

Nov 20 - Nov 30: 11 days

Dec 1 - Dec 9: 9 days

On December 9, she can still take her 3 doses.

By December 9, she will have taken 12 ml per day for 20 days for a total of 240 ml. She has 10 ml left for Dec 10th.

On Dec 10, she will take 2 doses of 4 ml and 1 dose of 2 ml, and she will finish the medicine.

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2 years ago

Please someone help me with this

stiks02 [169]

Answer:give me brainlist

Step-by-step explanation:

6 0

2 years ago

What is the greatest common factor of 4k, 18k4, and 12?

Setler [38]

Answer: The greatest common factor is 2.

Step-by-step explanation: We are given to find the greatest common factor of the following expressions:

$E_1=4k,~~E_2=18k^4,~~E_3=12.$

<u>Greatest Common Factor:</u> The GCF of two or more numbers (expressions) is the greatest factor that divides all the numbers or expressions.

We have

$E_1=4k=2\times 2\times k,\\\\E_2=18k^4=2\times 3\times 3\times k\times k\times k\times k,\\\\E_3=12=2\times 2\times 3.$

Therefore, the greatest common factor will be

$G.C.F.=2.$

Thus, the required greatest common factor is 2.

6 0

2 years ago

Read 2 more answers