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ivann1987 [24]
3 years ago
12

Suppose a population has 26 members identified with the letters A through Z.(a) You select one individual at random from this po

pulation. What is the probability of selecting individual A?(b) Assume person A gets selected on an initial draw, you replace person A into the sampling frame, and then take a second random draw. What is the probability of drawing person A on the second draw?(c) Assume person A gets selected on the initial draw and you sample again without replacement. What is the probability of drawing person A on the second draw?

Mathematics
1 answer:
Vanyuwa [196]3 years ago
4 0

Answer- The answer is below

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Step 1: 12x – 15 – 12x = 7x + 20
stealth61 [152]

Step-by-step explanation:

step 1. 12x - 15 - 12x = 7x + 20

step 2. 12x - 12x - 15 = 7x + 20 (grouping of terms)

step 3. -15 = 7x + 20 (adding like terms)

step 4. -35 = 7x (subtract 20 from both sides)

step 5. this step is incorrect.

step 6. -5 = x ( divide both sides by 7)

step 7. x = -5 (put the variable first).

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Answer:

How is this related to math?

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svlad2 [7]

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Step-by-step explanation:

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2 years ago
From first principles, find the indicated derivatives​
LenaWriter [7]

By definition of the derivative,

\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{(s + h)^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}

\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{s^3+3s^2h+3sh^2+h^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}

\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\frac{3s^2h+3sh^2+h^3}2}{h}

\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 \frac{3s^2h+3sh^2+h^3}{h}

\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 (3s^2+3sh+h^2)

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6 0
2 years ago
How can you use equivalent fractions to know that 43/200 is between 1/5 and 1/4
Vikki [24]
Multiply 1/5 and 1/4 so that everything has a common denominator of 200.

1/5*40/40 = 40/200
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7 0
3 years ago
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