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Aleks [24]
3 years ago
8

In this exercise you will debug the code which has been provided in the starter file. The code is intended to do the following:

Computers and Technology
1 answer:
abruzzese [7]3 years ago
8 0

Answer:

The corrected code is as follows:

import java.util.Scanner;

public class U2_L4_Activity_Two{

public static void main(String[] args){

Scanner scan = new Scanner(System.in);

String str1 = scan.nextLine();

String str2 = str1;

str1 = str1.toUpperCase();

System.out.println(str1);

System.out.println(str2);

}

}

Explanation:

This corrects the scanner object

Scanner scan = new Scanner(System.in);

This line is correct

String str1 = scan.nextLine();

This copies str1 to str2

String str2 = str1;

This converts str1 to upper case

str1 = str1.toUpperCase();

This prints str1

System.out.println(str1);

This prints str2

System.out.println(str2);

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3 years ago
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Return a version of the given string, where for every star (*) in the string the star and the chars immediately to its left and
lana [24]

Answer:

Explanation:

The following code is written in Java and uses a for loop with a series of IF ELSE statements to check the next and previous characters in a string. Checking to make sure that there are no asterix. If so it adds that character to the String variable output. Which is returned to the user at the end of the method. Two test cases have been created and the output can be seen in the attached image below.

class Brainly {

   public static void main(String[] args) {

       System.out.println(starOut("sm*eilly"));

       System.out.println(starOut("ab**cd"));

   }

   public static String starOut(String str) {

       String output = "";

       for (int i = 0; i < str.length(); i++) {

           if ((i != 0) && (i != str.length()-1)) {

               if ((str.charAt(i-1) != '*') && (str.charAt(i+1) != '*') && (str.charAt(i) != '*')) {

                   output += str.charAt(i);

               }

           } else {

               if ((i == 0) && (str.charAt(i) != '*') && (str.charAt(i+1) != '*')) {

                   output += str.charAt(i);

               } else if ((i == str.length()-1) && (str.charAt(i) != '*') && (str.charAt(i-1) != '*')) {

                   output += str.charAt(i);

               }

           }

       }

       return output;

   }

}

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3 years ago
Type the correct answer in the box. Spell all words correctly.
tiny-mole [99]

Answer:

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Explanation:

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Alisiya [41]
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3 0
3 years ago
When reading words using a Scanner object's next method, _________. a. any characters at the beginning of the input that are con
zavuch27 [327]

Answer:

The answer is "Option d"

Explanation:

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  • In option c, It is wrong because in this input before the call is not the method.
3 0
3 years ago
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