Use b for bicycles b and t for tricycles.
We know that each bicycle has 2 wheels, and each tricycle has 3 wheels, and if the entire number of wheels is 57, that means the
equation would be: 2b + 3t = 57
We can "separate" b by calling it "25 - t" as an alternative,
2(25 - t) + 3t = 57, or
50 - 2t + 3t = 57,
or 50 + t = 57, so
t = 7 So there must be 18 bicycles and 7 tricycles.
CHECKING:You can check this out by multiplying 7 tricycles x 3 wheels, which is 21,
and 18 bicycles x 2 wheels, which is 36
36 + 21 = 57
So i think u subtract how much money the person got and then subtract the answer by his pay.
Answer:
The sign is negative
Step-by-step explanation:
Given



Required
Determine the sign
The expression can be split into 3 factors

If x > 0 then x is positive and If y < 0 then y is negative
So, the expression becomes:

<em />
Leave only signs


So, we have:



So, we have:

<em>Hence, the sign of the expression is negative</em>
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Take for instance;


The expression would be:
-- negative
Answer:
for #14, x=10
Step-by-step explanation:
in the graph, 6x = 5x +10 so if x was 10 it would be 60 = 60 so x = 10
Note that f(x) as given is <em>not</em> invertible. By definition of inverse function,


which is a cubic polynomial in
with three distinct roots, so we could have three possible inverses, each valid over a subset of the domain of f(x).
Choose one of these inverses by restricting the domain of f(x) accordingly. Since a polynomial is monotonic between its extrema, we can determine where f(x) has its critical/turning points, then split the real line at these points.
f'(x) = 3x² - 1 = 0 ⇒ x = ±1/√3
So, we have three subsets over which f(x) can be considered invertible.
• (-∞, -1/√3)
• (-1/√3, 1/√3)
• (1/√3, ∞)
By the inverse function theorem,

where f(a) = b.
Solve f(x) = 2 for x :
x³ - x + 2 = 2
x³ - x = 0
x (x² - 1) = 0
x (x - 1) (x + 1) = 0
x = 0 or x = 1 or x = -1
Then
can be one of
• 1/f'(-1) = 1/2, if we restrict to (-∞, -1/√3);
• 1/f'(0) = -1, if we restrict to (-1/√3, 1/√3); or
• 1/f'(1) = 1/2, if we restrict to (1/√3, ∞)