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3 years ago

13

House numbers on one side of a street are conservative even integer the sum of the first three house numbers on the street is 62

16 what is the number of the third house

2 answers:

frozen [14]3 years ago

5 0

Should i do the work or just the answer :)

pantera1 [17]3 years ago

3 0

3103 I think that would be my best guesse

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The Molokai Nut Company (MNC) makes four different products from macadamia nuts grown in the Hawaiian Islands: chocolate-coated

lisabon 2012 [21]

Answer:

Profit = Selling price - Variable cost

Formulas:

F2 =SUMPRODUCT(B2:E2,$B$16:$E$16) copy to F2:F12, F14

Optimal solution: The company should produce the following quantities (in pounds) of the four varieties of nuts.

Whole = 1000

Cluster = 500

Crunch = 80

Roasted = 200

Total profit = $ 2913.20

Step-by-step explanation:

3 0

3 years ago

Solve the equation using the substitution u = y/x. When u = y/x is substituted into the equation, the equation becomes separable

bekas [8.4K]

Answer:

$\frac{u^2+3}{-u^3+u^2-2u}u'=\frac{1}{x}$

Step-by-step explanation:

First step: I'm going to solve our substitution for y:

$u=\frac{y}{x}$

Multiply both sides by x:

$ux=y$

Second step: Differentiate the substitution:

$u'x+u=y'$

Third step: Plug in first and second step into the given equation dy/dx=f(x,y):

$u'x+u=\frac{x(ux)+(ux)^2}{3x^2+(ux)^2}$

$u'x+u=\frac{ux^2+u^2x^2}{3x^2+u^2x^2}$

We are going to simplify what we can.

Every term in the fraction on the right hand side of equation contains a factor of $x^2$ so I'm going to divide top and bottom by $x^2$ :

$u'x+u=\frac{u+u^2}{3+u^2}$

Now I have no idea what your left hand side is suppose to look like but I'm going to keep going here:

Subtract u on both sides:

$u'x=\frac{u+u^2}{3+u^2}-u$

Find a common denominator: Multiply second term on right hand side by $\frac{3+u^2}{3+u^2}$ :

$u'x=\frac{u+u^2}{3+u^2}-\frac{u(3+u^2)}{3+u^2}$

Combine fractions while also distributing u to terms in ( ):

$u'x=\frac{u+u^2-3u-u^3}{3+u^2}$

$u'x=\frac{-u^3+u^2-2u}{3+u^2}$

Third step: I'm going to separate the variables:

Multiply both sides by the reciprocal of the right hand side fraction.

$u' \frac{3+u^2}{-u^3+u^2-2u}x=1$

Divide both sides by x:

$\frac{3+u^2}{-u^3+u^2-2u}u'=\frac{1}{x}$

Reorder the top a little of left hand side using the commutative property for addition:

$\frac{u^2+3}{-u^3+u^2-2u}u'=\frac{1}{x}$

The expression on left hand side almost matches your expression but not quite so something seems a little off.

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3 years ago

ILL GIVE YOU THE BRAINLEST IF YOU ANSWER MY QUESTION CORRECTLY

Temka [501]

Answer:

Is this correct?

Step-by-step explanation:

idk

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3 years ago

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Solve 1/3b + 57 = 3

Sladkaya [172]

Answer: b=-18

Step-by-step explanation:

1/3b+57=3

Subtract 57

1/3b=-54

Divide by 1/3 (basically you’re dividing by 3)

p=-18

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3 years ago

HELPPPP I only have one try left!!<br> PEMDAS!!!

Gnesinka [82]

Answer:

39

Step-by-step explanation:

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3 years ago

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