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3 years ago

13

How many telephone numbers are there in the 509 area code? Telephone numbers may not start with the number 0 or 1. They also mus

t not begin with 911 or 555. Do not consider other special circumstances.

1 answer:

anastassius [24]3 years ago

4 0

There are 1798 telephone numbers in the area if I am not wrong and PLEASE mark me Brainliest

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If the area of the circle is 28 in^2,what is the area of the shaded sector with 90 degree angle?

Nutka1998 [239]

That would be 1/4 * 28 = 7 ins^2

7 0

3 years ago

Assume the sample below is a perfectly random sample of students at a school. How much greater is the mean of the

igor_vitrenko [27]

Answer:

0.75

Step-by-step explanation:

The table is not well presented (See Attachment)

There are at least two approaches to this question

Method 1:

Steps

1. Calculate the mean of reported heights

Mean of reported heights = (61+68+57.5+48.5+75+65+80+68+69+63)/10

Mean of reported heights = 655/10

Mean of reported heights = 65.5

2. Calculate the mean of measured heights

Mean of measured heights = (62 + 68 + 56.5 + 47 + 72 + 65 + 78 + 67 + 69.5 + 62.5)/10

Mean of measured heights = 647.5/10

Mean of measured heights = 64.75

3. Get their difference

Difference = Mean of reported heights - Mean of measured heights

Difference = 65.5 - 64.75

Difference = 0,75

Method 2: Calculate the mean of their difference

Mean of difference = Sum of difference / Number of observations

Mean of difference = (-1 + 0 + 1 + 1.5 + 3 + 0 + 2 + 1 – 0.5 + 0.5)/10

Mean of difference = 7.5/10

Mean of difference = 0.75

Note that in both cases, the result is 0,75.

Hence, the reported heights at the school is 0.75 greater than the actual measured height

3 0

2 years ago

Read 2 more answers

New York City is approximately 205 miles from Washington, D.C. How far apart will these cities appear on a map with the scale 1

gavmur [86]

Answer: 4.1 inches

Step-by-step explanation:

From the question, we are informed that New York City is approximately 205 miles from Washington, D.C.

The distance that these cities will appear on a map with the scale 1 in: 50 miles will be represented by x.

Therefore, x:205 = 1:50

Cross multiply

x/205 = 1/50

50x = 205

x = 205/50

x = 4.1 inches

The answer is 4.1 inches

4 0

3 years ago

Factor the expression.<br> 9y^2– 36

Nata [24]

Answer:

Answer: 9 (y - 2) (y + 2)

Step-by-step explanation:

Factor the following:

9 y^2 - 36

Factor 9 out of 9 y^2 - 36:

9 (y^2 - 4)

y^2 - 4 = y^2 - 2^2:

9 (y^2 - 2^2)

Factor the difference of two squares. y^2 - 2^2 = (y - 2) (y + 2):

Answer: 9 (y - 2) (y + 2)

5 0

3 years ago

A total of 1 232 students have taken a course in Spanish, 879 have taken a course in French, and 114 have taken a course in Russ

ElenaW [278]

Answer:

$n(S\cap F \cap R)=7$

Step-by-step explanation:

The Universal Set, n(U)=2092

$n(S)=1232\\n(F)=879\\n(R)=114$

$n(S\cap R)=23\\n(S\cap F)=103\\n(F\cap R)=14$

Let the number who take all three subjects, $n(S\cap F \cap R)=x$

Note that in the Venn Diagram, we have subtracted $n(S\cap F \cap R)=x$ from each of the intersection of two sets.

The next step is to determine the number of students who study only each of the courses.

$n(S\:only)=1232-[103-x+x+23-x]=1106+x\\n(F\: only)=879-[103-x+x+14-x]=762+x\\n(R\:only)=114-[23-x+x+14-x]=77+x$

These values are substituted in the second Venn diagram

Adding up all the values

2092=[1106+x]+[103-x]+x+[23-x]+[762+x]+[14-x]+[77+x]

2092=2085+x

x=2092-2085

x=7

The number of students who have taken courses in all three subjects, $n(S\cap F \cap R)=7$

3 0

3 years ago