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STatiana [176]
3 years ago
13

Find the circumference and area of a circle that has a radius of x+1

Mathematics
1 answer:
lbvjy [14]3 years ago
6 0
Circumference: 2πr
Circumference: 2(3.14)(x + 1)
Circumference: 6.28(x + 1)
Circumference: 6.28(x) + 6.28(1)
Circumference: 6.28x + 6.28

Area: πr²
Area: 3.14(x + 1)²
Area: 3.14(x  +1)(x + 1)
Area: 3.14(x(x + 1) + 1(x + 1))
Area: 3.14(x(x) + x(1) + 1(x)  1(1))
Area: 3.14(x² + x + x + 1)
Area: 3.14(x² + 2x + 1)
Area: 3.14(x²) + 3.14(2x) + 3.14(1)
Area: 3.14x² + 6.28x + 3.14
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Solve 4 −6<br><br> s −83<br><br> Thank you in advance
aleksandr82 [10.1K]

Answer:

Alright, so we have 4 - 6 = s - 83.

This means

-2 = s - 83

Add 83 to both sides to get:

81 = s

s = 81 :)

7 0
3 years ago
Cot(x)=-3. find sin(x)
ASHA 777 [7]

Answer:

sin(x)=1/\sqrt10

Step-by-step explanation:

The trigonometric identities involve trigonometric functions. Here we will be using Trigonometric identity

sin²x  = 1 /( 1+cot²x )

now cot(x)= -3

⇒ cot²x= (-3)²

⇒ cot²x= 9

sin²x= 1/( 1+9)

⇒ sin²x = 1/10

taking under root on both the sides we get

√sin²x=\sqrt1/\sqrt10

⇒ sin(x)=± 1/\sqrt10

6 0
3 years ago
If r = 18 and t = 6, what is the value of the following expression?<br> r + 42 ÷ t · 5
AleksAgata [21]

Answer:

53

Step-by-step explanation:

42/6=7

7*5=35

18+35=53

4 0
3 years ago
How do you solve x^4-16x^2-720=0
kirill115 [55]

Answer:x

=

6

,

−

6

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2

i

√

5

,

−

2

i

√

5

7 0
3 years ago
Solve 5x^2+2x=1 using either factoring, square root method, completing the square or quadratic formula.
wolverine [178]

Answer:

x = -1 ± √6 / 5

Step-by-step explanation:

Solve 5x^{2} + 2x = 1

move 1 to the left side of the equation by subtracting it from both sides.

5x^{2} + 2x - 1 = 0

Use the quadratic formula to find the solutions.

-b± \sqrt{b^2 - 4 (ac)}/ 2a

Substitute the values a = 5 , b = 2, and c = -1 into the quadratic formula and solve for x

-2±\sqrt{2^2 - 4(5 - 1)}/ 2 ⋅ 5

Simplify.

x = -2 ± 2 \sqrt{6}/ 10

x = -1 ± \sqrt{6}/ 5

Exact Form:

x = -1 ± \sqrt{6}/ 5

4 0
3 years ago
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