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2 years ago

Find the 14th term of the geometric sequence 9, 18, 36

Mathematics

1 answer:

diamong [38]2 years ago

5 0

Answer:

9 × 2^(13)

Step-by-step explanation:

hello :

the nth term is : An =A1 × r^(n-1)

a common ratio is : r and A1 the first term

in this exercice : r= -3-(-7)36/18 = 18/9 =2 A1 = 9

when : n =14 you have the 14rd term A14

A14 = 9 × 2^(14-1) = 9 × 2^(13)

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<h3>Trigonometric ratios</h3>

It is important to note that

sin A = opposite/ hypotenuse

cos A = adjacent/ hypotenuse

Then,

opposite = $\sqrt{1} - x$

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Learn more about trigonometric identities here:

brainly.com/question/7331447

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