DNA testing can be used to search for your genetic ancestors.
Answer:
The fraction of the offspring that will show the phenotype produced by the recessive c allele is 1024/4096 = 0.25 A-BbccDdE-Ff = 25%
Explanation:
You can calculate the fraction of the offspring that will show the phenotype produced by the recessive c allele by making the punnet square for each gene and then multipling the phenotypic proportions, like this:
Cross) AAbbCcDDEeff x AaBBCcddEEFF
Cross For each gene by separately:
Gametes) A A A a
F1) 2/4 AA
2/4 Aa
Gametes) b b B b
F1) 4/4 Bb
Gametes) C c C c
F1) 1/4 CC
2/4 Cc
1/4 cc
Gametes) D D d d
F1) 4/4 Dd
Gametes) E e E E
F1) 2/4 Ee
2/4 EE
Gametes) f f F F
F1) 4/4 Ff
So, fraction of the offspring that will show the phenotype produced by the recessive c allele is:
4/4 A- x 4/4 Bb x 1/4 cc x 4/4 Dd x 4/4 E- x 4/4 Ff =
1024/4096 = 0.25 A-BbccDdE-Ff =25%
Answer: Animals use only respiration, while plants use both photosynthesis and respiration.
Answer:
The correct answer is option d.
Explanation:
The production of Acetyl-CoA takes place by the dissociation of both carbohydrates and lipids in the process of glycolysis and beta-oxidation. It then moves into the TCA cycle in the mitochondria and combines with oxaloacetate to give rise to citrate.
In the given case, no labeling will be found in the acetyl-CoA. The labeled C3 and C4 carbon of glucose signify the carboxyl carbon of pyruvate. In the succeeding reactions of the transformation of pyruvate to acetyl-CoA, the carboxyl carbon gets lost in the form of carbon dioxide. Thus, acetyl-CoA does not comprise any labeled C3 and C4 of glucose.
