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viktelen [127]
2 years ago
8

Alicia wants to cover a footrest in the shape of a rectangular prism with cotton fabric. The footrest is 14 inches by 11 inches

by 13 inches. She has 1 square yard of fabric. Can she completly cover the footrest
Mathematics
1 answer:
kati45 [8]2 years ago
7 0

Answer:

Since the footrest measures 1.54 square yards, Alice will not be able to cover it completely.

Step-by-step explanation:

Since Alicia wants to cover a footrest in the shape of a rectangular prism with cotton fabric, and the footrest is 14 inches by 11 inches by 13 inches while she has 1 square yard of fabric, to determine if she can she completly cover the footrest the following calculation must be performed:

1 square yard = 1296 square inches

14 x 11 x 13 = X

154 x 13 = X

2.002 = X

2.002 / 1.296 = 1.54

Thus, since the footrest measures 1.54 square yards, Alice will not be able to cover it completely.

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7 0
3 years ago
The life in hours of a biomedical device under development in the laboratory is known to be approximately normally distributed.
Anton [14]

Answer:

a) The evidence suggest the true mean life of a biomedical device > 5500

b) (5487.94, +∞)

c) There is evidence to support that the mean is equal to 5500

Step-by-step explanation:

Here we have

(a) To test the hypothesis we have the claim that the mean life of biomedical devices > 5500

Therefore, we put the null Hypothesis which is the proposition that a difference does not exist. That is

H₀:  μ = 5500

Therefore, the alternative hypothesis will be

Hₐ:  μ > 5500

The test statistic is then found by;

t=\frac{\bar{x}-\mu }{\frac{s }{\sqrt{n}}} =\frac{5617.8-5500 }{\frac{234.5 }{\sqrt{15}}} \approx 1.95

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0.025 < P < 0.05

The P value is given as 0.036 from the T distribution at 14 derees of freedom df

Therefore, since P < α or 0.05, we reject the null hypothesis. That is we fail to reject Hₐ:  μ > 5500. The evidence suggest the true mean life of a biomedical device > 5500

(b) The 95% confidence interval is given as

CI=\bar{x}\pm t_\alpha \frac{s}{\sqrt{n}}

Which gives    t_\alpha =  \pm2.145

CI=5617.8\pm 2.145 \times \frac{234.5}{\sqrt{15}}

The confidence interval of the lower bound on the mean is then

(5487.94, +∞)

c) From the above result, we find that the mean of 5500 is contained in the range of the lower confidence on the mean. We can therefore, accept the null hypothesis. That is there is evidence to support that the mean is equal to 5500.

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3 years ago
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3 years ago
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<u>Let's solve this problem step-by-step</u>:

 \frac{3v}{7} =6\\\frac{3v}{7} *1=6\\\frac{3v}{7} *\frac{7}{7}=6\\ 3v = 6 * 7\\3v=42\\v=14

<u>Thus v = 14</u>

<u />

<u>Answer: v= 14</u>

<u></u>

Hope that helps!

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