Answer:
The constant of proportionality is equal to 4
Step-by-step explanation:
The picture of the question in the attached figure
Let
y ----> the total cost in dollars
x ----> the number of bags of peanuts
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form 
or 
To find out the constant of proportionality, we need to take one point from the graph
take the point (1,4)
Find the value of k
substitute the value of x and the value of y
Answer:
0.5<2-√2<0.6
Step-by-step explanation:
The original inequality states that 1.4<√2<1.5
For the second inequality, you can think of 2-√2 as 2+(-√2).
Because of the "properties of inequalities", we know that when a positive inequality is being turned into a negative, the numbers need to swap and become negative. So, the original inequality becomes -1.5<-√2<-1.4. (Notice how the √2 becomes negative, too). This makes sense because -1.5 is less than -1.4.
Using our new inequality, we can solve the problem. Instead of 2+(-√2), we are going to switch "-√2" with both possibilities of -1.5 and -1.6. For -1.5, we would get 2+(-1.5), or 0.5. For -1.4, we would get 2+(-1.4), or 0.6.
Now, we insert the new numbers into the equation _<2-√2<_. The 0.5 would take the original equation's "1.4" place, and 0.6 would take 1.5's. In the end, you'd get 0.5<2-√2<0.6. All possible values of 2-√2 would be between 0.5 and 0.6.
Hope this helped!
Answer:
A and C
Step-by-step explanation:
Answer:
x=6
Step-by-step explanation:
In a square, its angles are all 90 degrees. So, cutting a square in half into two triangles from corner to corner produces 45 degree angles on both sides. Since the triangles are now 45-45-90 triangles, we can use the rule where the hypotenuse of the triangle is equal to the square root of 2 times the length of either side. So, the side length is 6.
Draw out a number line. Make sure 4 is on the number line. At this location, plot an open circle. The open circle indicates "do not include this endpoint as part of the solution set". We shade to the right of this open circle.
Visually this describes all real numbers that are larger than 4.
