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meriva
3 years ago
13

Match each table showing a proportional relationship between x and y with its constant of proportionality.

Mathematics
1 answer:
UkoKoshka [18]3 years ago
6 0

Answer:

Table 1 is 4. Table 2 is 2. Table 3 is 1.5. Table 4 is 6.

Step-by-step explanation:

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For any real number r, which of the following must be greater than r?
adelina 88 [10]
C) r^2 + 1 because any number squared (positive or negative) will be positive
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3 years ago
How do you write the slope intercept for 3x=9y
bagirrra123 [75]
3x = 9y
9y = 3x
y = 3x/9
y = 1/3x

<span>The slope is 1/3</span>
5 0
4 years ago
I can't figure this out
kumpel [21]

The equation of the function g(x) will be g(x) = - ln (x + 2).

<h3>What is a logarithm?</h3>

Exponents can also be written as logarithms. A number base logarithm is similar to some other number. It is the exact inverse of the exponent expression.

Let the equation of the function f will be

f(x) = ln x

If the function is multiplied with negative sign, then the function gets flipped about the x-axis.

And if we add 2 in the variable of the function, then the function gets shifted towards left.

Then the equation of the function g(x) will be

g(x) = - ln (x + 2)

More about the logarithm link is given below.

brainly.com/question/7302008

#SPJ1

8 0
2 years ago
Set A contains all integers from 50 to 100 inclusive, Set B contains all integers from 69 to 138 exclusive. How many integers ar
mario62 [17]
Answer: C. 31

Explanation:
Set A contains [50, 51, 52, … , 99, 100]. Set B contains [70, 71, 72, … , 136, 137]

Notice that Set B and Set A have an overlap from 70 to 100. So that is 31 elements in total. Hence the set A intersect B is [70, 71, 72, … , 99, 100] which is 31 elements.

Cheers.
8 0
2 years ago
A study reveals that 65% of homeowners in Omaha own a lawn mower. To test this claim, you form a sample of 500 homeowners in Oma
kotegsom [21]

Answer:

There is no enough evidence to reject the claim using a level of significance of 5%

Step-by-step explanation:

Let p be the true proportion of homeowners in Omaha who own a lawnmower. We want to test  

H_{0}: p = p_{0} = 0.65 vs H_{1}: p\neq 0.65 (two-tailed alternative).

We have a large sample of size n = 500 and a point estimate for p is \hat{p}=0.68. The test statistic is given by

Z=\frac{\hat{p}-p_{0}}{\sqrt{p_{0}(1-p_{0})/n}}=\frac{0.68-0.65}{\sqrt{0.65(1-0.65)/500}} where \sqrt{0.65(1-0.65)/500} is the standard error of \hat{p} when H_{0} is true. The observed value is z_{0} = 1.4064 which comes from a standard normal distribution. Because we want to use a level of significance of 5%, our rejection region is RR={z | z < -1.96 or z > 1.96} where -1.96 and 1.96 are the 2.5th and 97.5th quantiles respectively. Because 1.4064 does not belong to RR, we fail to reject the null hypothesis.

6 0
3 years ago
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