The figure is not attached. So we will assume a rectangle that has sides of lengths 2 cm and width 3 cm and It is enlarged<span> with scale factor 3.
</span><span>The width of the original rectangle must be one-third of the enlarged rectangle.
</span>The lengths of the sides of the enlarged rectangle will be:
<span>3 × 2 cm = 6 cm (Length)
<span>3 × 3 cm = 9 cm (Width)</span></span>
First convert the terms to fractional exponents
u = t^2/3 - 3t^3/2
differentiating
u' = 2/3 t^ (2/3 - 1) - 3* 3/2 t^(3/2 - 1)
= 2/3 t ^(-1/3) - 9/2 t ^(1/2)
= 2 / (3∛t) - 9 √ t / 2 in radical form
Answer:
A: 2/3
Step-by-step explanation:
24w+6c=$23.40
5w+2c=$6.60
So you have to find c (chips) first. You have to make the number of chips in both equations cancel each other.
-3(5w+2c)=-3($6.60)
-15w-6c=$-19.80
Then subtract to get one formula
24w + 6c = $23.40
-15w - 6c = $-19.80
9w = $3.60
w=$.40
To check your answer, find how much one bag of chips costs:
5($.40) + 2c = $6.60
$2.00 + 2c = $6.60
2c = $4.60
c=$2.30
Plug your value for one water and one bag of chips into the formula:
5($.40) + 2($2.30)
$2.00 + $4.60
=$6.60
Then plug your values into the original problem:
24($.40) + 6($2.30)
$9.60 + $13.80
=$23.40