Given Information:
Population mean = p = 60% = 0.60
Population size = N = 7400
Sample size = n = 50
Required Information:
Sample mean = μ = ?
standard deviation = σ = ?
Answer:
Sample mean = μ = 0.60
standard deviation = σ = 0.069
Step-by-step explanation:
We know from the central limit theorem, the sampling distribution is approximately normal as long as the expected number of successes and failures are equal or greater than 10
np ≥ 10
50*0.60 ≥ 10
30 ≥ 10 (satisfied)
n(1 - p) ≥ 10
50(1 - 0.60) ≥ 10
50(0.40) ≥ 10
20 ≥ 10 (satisfied)
The mean of the sampling distribution will be same as population mean that is
Sample mean = p = μ = 0.60
The standard deviation for this sampling distribution is given by

Where p is the population mean that is proportion of female students and n is the sample size.

Therefore, the standard deviation of the sampling distribution is 0.069.
Answer:
This is the best solution for your question
Answer:
Step-by-step explanation:
2x⁴ + 4x³ - 30x² = 2x²*(x² + 2x - 15)
x² + 2x - 15
Sum = 2
Product = -15
Factors = 5 ; (-3)
x² + 2x - 15 = x² + 5x - 3x - 3 *5
= x(x + 5) - 3(x + 5)
= (x + 5)(x - 3)
2x⁴ + 4x³ - 30x² = (2x²) (x + 5)(x - 3)
∠DBC = 19° since the two angles have to add up to 180, if x = 23, then 23 -4 = 19 for the right, and 7 x 23 = 161, and 161 + 19 = 180.
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