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meriva
3 years ago
13

Match each table showing a proportional relationship between x and y with its constant of proportionality.

Mathematics
1 answer:
UkoKoshka [18]3 years ago
6 0

Answer:

Table 1 is 4. Table 2 is 2. Table 3 is 1.5. Table 4 is 6.

Step-by-step explanation:

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Please help me with this !
SSSSS [86.1K]

Answer:

mE=mC

mD=mB

Step-by-step explanation:

thats should be correct

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Kilani bought a cell phone service plan that provides 300 minutes of phone use each month. Use a unit multiplier to convert 300
Juli2301 [7.4K]
300 minutes converted into hours would be 5 hours
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Please help asap for brainlist
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3 years ago
List the integers that satisfy both these inequalities.<br> 2x + 9 &lt; 0<br> x&gt;-12
Shkiper50 [21]

We have been given two inequalities 2x+9 and x>-12. We are asked to find the integers that satisfy both inequalities.

Let us solve for our 1st inequality.

2x+9-9

2x

\frac{2x}{2}

x

Upon combining our both inequalities, we will get:

-12

This means that solution of our inequalities is x values greater than -12 and less than -4.5.

We know that integers between -12 and -4.5 are: -11,-10,-9,-8,7,-6,-5.

Therefore, our solution would be x=\{-11,-10,-9,-8,7,-6,-5\}.

6 0
3 years ago
Read 2 more answers
You work at a job where your average monthly earnings are $682 with a standard deviation of $49. Your mean monthly expenses are
Pavel [41]

Answer:

S = I-E.

We can find the expected value of S and we got:

E(S) = E(I-E) = E(I) -E(E)= 682-211=471

And that represent the mean of the amount of money into your savings account each month

And now we can find the variance of the random variable S like this:

Var(S) = Var(I-E) = Var(I) +Var(E) - 2Cov(I,E)

And since we know that Cov (I,E) =0 then we have:

Var(S) = Var(I) + Var(E) = 49^2 + 16^2 = 2657

And then the deviation would be:

Sd(S) = \sqrt{2657}= 51.546

And that represent the standard deviation of the amount of money you put in your savings account each month

Step-by-step explanation:

Let I the random variable that represent the income for each month and we know:

E(I) = 682, \sigma_I = 49

Let E the random variable that represent the monthly expenses for each month and we know:

E(E)= 211, \sigma_E = 16

And for this case we know that the random variables I and E are independent, so then Cov(I, E) = 0

We can define the random variable S representing the amount that we can save each month and we can define S = I-E.

We can find the expected value of S and we got:

E(S) = E(I-E) = E(I) -E(E)= 682-211=471

And that represent the mean of the amount of money into your savings account each month

And now we can find the variance of the random variable S like this:

Var(S) = Var(I-E) = Var(I) +Var(E) - 2Cov(I,E)

And since we know that Cov (I,E) =0 then we have:

Var(S) = Var(I) + Var(E) = 49^2 + 16^2 = 2657

And then the deviation would be:

Sd(S) = \sqrt{2657}= 51.546

And that represent the standard deviation of the amount of money you put in your savings account each month

3 0
4 years ago
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