All categories

3 years ago

Match each table showing a proportional relationship between x and y with its constant of proportionality.

Mathematics

1 answer:

UkoKoshka [18]3 years ago

6 0

Answer:

Table 1 is 4. Table 2 is 2. Table 3 is 1.5. Table 4 is 6.

Step-by-step explanation:

You might be interested in

The front of the stage, side C , is 50 feet long. A 40-foot rope runs along the side of square B. A 30-foot rope runs along the

vovangra [49]

Answer: yes, because any triangle with the ratio of whole number 3:4:5 is a right triangle

Step-by-step explanation:

8 0

3 years ago

Area of irregular figures uhmmm

Ann [662]

Answer:

146

Step-by-step explanation:

4×12+5×10+4×12=146

3 0

3 years ago

Katie it making necklaces. She has 1/3 of blue ribbon 3/4 yard of pink ribbon & 7/8 yard of green ribbon. write the ribbon l

german

In order from greatest to least, the ribbons go

7/8 (Green)
3/4 (Pink)
1/3 (Blue)

This because 7 out of 8 is a larger number than 3 out of 4, and 3 out of 4 is greater than 1 out of 3.

8 0

3 years ago

Write .139 as a percent.

Rama09 [41]

Answer:

13.9%

Step-by-step explanation:

0.139 x 100=13.9, can you give me brainiest if its correct

4 0

3 years ago

Read 2 more answers

A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions

salantis [7]

Dimensions are length 20 meter and width 14 meter

Solution:

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

A rectangle has width that is 6 meters less than the length

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

The area of the rectangle is given by formula:

$Area = length \times width$

Substituting the values we get,

$Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0$

Solve the above equation by quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}$

$a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14$

Since, length cannot be negative, ignore a = -14

Thus solution of length is a = 20

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

6 0

3 years ago