F(1) = (1)^3 + 2(1)^2 - 5(1) - 6 = 1 + 2 - 5 - 6 = -8; x = 1 is not a solution to the polynomial.
f(-1) = (-1)^3 + 2(-1)^2 - 5(-1) - 6 = -1 + 2 + 5 - 6 = 0; x = -1 is a solution to polynomial.
From the options, a or c has x = -1, both has x = , so lets check for x = 3
f(3) = (3)^3 + 2(3)^2 - 5(3) - 6 = 27 + 18 - 15 - 6 = 24; x = 3 is not a solution to the polynomial.
Therefore the solutions to the polynomial are x = -3, x = -1, x = 2
Answer:
VRT AND WRS
Step-by-step explanation:
it's not possible for the others to be vertical angles like VRU and TRS are not the same on opposite sides.
Answer:
The hole is 9 inches deep
Step-by-step explanation:
Volume of a cubicle hole = a^3
Where a= side edge of the cube
Volume of dirt removed = 729 cubic inches
How many inches deep is the hole
Volume of a cubicle hole = a^3
729 = a^3
Find the cube root of both sides
3√729 = 3√ a^3
9 = a
a= 9 inches
The hole is 9 inches deep
Check:
9^3
=9 *9*9
= 729
Answer:
Step-by-step explanation:
<u>Measure of the inscribed angle is half the arc measure:</u>
- x = m∠ABC = 1/2mAC
- x = 1/2(82°) = 41°
Answer:
us set up the following variables:
⎧
⎪
⎪
⎪
⎪
⎨
⎪
⎪
⎪
⎪
⎩
l
Length of Rectangle (cm)
w
Width of Rectangle (cm)
A
Area of Rectangle (
c
m
2
)
t
Time (s)
We are told that:
d
l
d
t
=
8
cm/s (const), and,
d
w
d
t
=
3
cm/s (const)
The Area of the rectangle is:
A
=
l
w
Differentiating wrt
t
(using the product rule) we get;
d
A
d
t
=
(
l
)
(
d
w
d
t
)
+
(
d
l
d
t
)
(
w
)
∴
d
A
d
t
=
3
l
+
8
w
So when
l
=
20
and
w
=
10
⇒
d
A
d
t
=
3
⋅
20
+
8
⋅
10
∴
d
A
d
t
=
60
+
80
∴
d
A
d
t
=
140
cm