∠A and \angle B∠B are complementary angles. If m\angle A=(x+16)^{\circ}∠A=(x+16) ∘ and m\angle B=(x-12)^{\circ}∠B=(x−12) ∘ , the
1 answer:
You might be interested in
1. The major arc ED has measure 180 degrees since ED is a diameter of the circle. The measure of arc EF is , so the measure of arc DF is
The inscribed angle theorem tells us that the central angle subtended by arc DF, , has a measure of twice the measure of the inscribed angle DEF (which is the same angle OEF) so
so the measure of arc DF is also 64 degrees. So we have
###
2. Arc FE and angle EOF have the same measure, 56 degrees. By the inscribed angle theorem,
Triangle DEF is isosceles because FD and ED have the same length, so angles EFD and DEF are congruent. Also, the sum of the interior angles of any triangle is 180 degrees. It follows that
Triangle OFE is also isosceles, so angles EFO and FEO are congruent. So we have
a) The halfway number is .
b) The ascending order is ,
and
.
<u>Step-by-step explanation:</u>
a)Halfway number is otherwise Middle number.
The halfway number of two numbers = .
The halfway for and
=
.
=.
= .
=.
∴Halfway =.
=
The halfway for and
=
.
b) The ascending order is ,
and
.