Answer: the following are required for IV-3 to have condition
Explanation:
-II-4 passes an X b chromosome to III-4 (probability = 1/2).
-If III-4 has the genotype X B X b (accounted for by the above probability), then she passes an X b chromosome to IV-3 (probability = 1/2).
-III-5 passes a Y chromosome to IV-3 (probability = 1/2).
All of these requirements are needed in sequence, so you apply the product rule here, too (1/2 x 1/2 x 1/2 = 1/8).
Once the individual probabilities are known, the sum and/or product rules can be used for various combinations (both conditions, either condition, etc.).
The coefficient of the second term is the 3 in (4x+3y)
The answer would be 12 3/4 because when you continue use the pattern that is used you end up with your answer! Hope this helps
Ending slavery and ending women sufferage
Answer: Q=240/11
Step-by-step explanation: