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Sergeeva-Olga [200]

3 years ago

15

Which are reasonable solutions for this situation if x represents the number of hot dogs sold and y represents the number of bot

tles of water sold? Check all that apply.
(–1, 5)
(0, 6)
(2, 1)
(1, 1.5)
(1, 3)
(2, 2)

1 answer:

Novosadov [1.4K]3 years ago

4 0

Do you have more to thus problem??

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The population of Tinyville is 16.2 Tinys per acre. Exactly 405 Tinys live in Tinyville. How many acres is Tinyville? Only enter

Mice21 [21]

The answer is 25 because 405/16.2=25.

8 0

3 years ago

5-2(a+3b)/2 When a=4 and b=1.

nirvana33 [79]

Hello macelynn190!

$\huge \boxed{\mathfrak{Question} \downarrow}$

$\huge \tt \frac{5 - 2(a + 3b)}{2}$

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

To solve this question we need to substitute the given values of 'a' & 'b' in the equation & then simplify it.

Given,

a = 4
b = 1

Now, substitute this in the place of 'a' & 'b'..

$\large \tt \frac{5 - 2(a + 3b)}{2} \\ = \large \underline{\underline{\tt \: \frac{5 - 2((4) + 3(1))}{2} }}$

Lastly, simplify it...

$\large \tt \: \frac{5 - 2((4) + 3(1))}{2} \\ = \large \tt\frac{5 - 2(4 + 3)}{2} \\ = \large \tt \: \frac{5 - 2(7)}{2} \\ = \large \tt \: \frac{5 - 14}{2} \\ = \large \tt\frac{-9}{2} \\ = \large \boxed{\boxed{ \bf \: -\frac{9}{2}=-4.5}}$

The answer is <u>-</u><u>9</u><u>/</u><u>2</u><u> </u><u>or </u><u>-</u><u>4</u><u>.</u><u>5</u>

__________________

Hope it'll help you!

ℓu¢αzz ッ

5 0

2 years ago

Read 2 more answers

Boxes of raisins are labeled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is r

ZanzabumX [31]

Answer:

A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Step-by-step explanation:

We are given the weights, in the ounces, of a sample of 12 boxes below;

Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = $\frac{\sum X}{n}$ = 21.88 ounces

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 0.201 ounces

n = sample of boxes = 12

$\mu$ = population mean weight

<em>Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.</em>

<u>So, 90% confidence interval for the population mean, </u> $\mu$ <u> is ;</u>

P(-1.796 < $t_1_1$ < 1.796) = 0.90 {As the critical value of t at 11 degrees of

freedom are -1.796 & 1.796 with P = 5%}

P(-1.796 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.796) = 0.90

P( $-1.796 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

<u>90% confidence interval for</u> $\mu$ = [ $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $21.88-1.796 \times {\frac{0.201}{\sqrt{12} } }$ , $21.88+1.796 \times {\frac{0.201}{\sqrt{12} } }$ ]

= [21.78, 21.98]

Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

8 0

3 years ago

The coordinates of the verticies of a rectangle are (-2,3), (4,3), (4,-4) and (-2, -4) what are the demensions of the rectangle?

kolbaska11 [484]

Jdushuszvusshsushduys sudbrhr did for fun dbd d d did. B. B u igfuf.

6 0

3 years ago

The quotient of a number and 14 is 8. Find the number.

mafiozo [28]

Answer:

The number is 112

Step-by-step explanation:

Let the number be 'x'

$\sf \dfrac{x}{14}=8\\\\\text{Multiply both sides by 14}\\\\ \dfrac{x}{14}*14=8*14\\\\$

<h3> x = 112</h3>

5 0

2 years ago

Read 2 more answers