3 years ago

Which system has no solutions?

Mathematics

1 answer:

ale4655 [162]3 years ago

5 0

Answer:

the answer is C. x<3 x<1 that is the answer

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In B, the percent is 35%. What is the part and what is the whole?

devlian [24]

The part is 21 and the whole is 60

hope this helps. God bless

5 0

3 years ago

How many solutions does this equation have? x=x+9

Tju [1.3M]

Answer:

no solutions

Step-by-step explanation:

x = x + 9

x - x = 9

0 = 9

it's false

7 0

3 years ago

If the club decides to send 5 members to the convention, how many different groups of 5 are possible? there are 10 members

hodyreva [135]

For the 1st member, you have 10 possible choices.

For the 2nd, you have 9 remaining choices.

For the 3rd: 8.

So all possible combinations would be:
10*9*8*7*6 = 10! - 5! = 30,240 combinations.

7 0

3 years ago

If 4 × 5 = 20, then 20 ÷ 4 equals what number?

JulijaS [17]

Answer:

20 ÷ 4 = 5

(Brainliest please! :D)

4 0

3 years ago

A trapezoid has base lengths of 12 centimeters and 13 centimeters. The other sides have lengths of 5 centimeters and 10 centimet

r-ruslan [8.4K]

Answer:

The area of the composite figure is 392.12 $cm^{2}$ .

Step-by-step explanation:

The area of the composite figure = area of trapezoid + area of rectangle

Area of trapezium = $\frac{1}{2}$ ( a +b)h

Where: a is the length of the first base, b the length of the second base and h is the height of the trapzium.

Applying Pythagoras theorem, the height, h, is;

h = $\sqrt{5^{2} - 1^{2} }$

= $\sqrt{24}$

h = 2 $\sqrt{6}$

Area of trapezium = $\frac{1}{2}$ ( a +b)h

= $\frac{1}{2}$ (13 + 12) × 2 $\sqrt{6}$

= 156 $\sqrt{6}$

= 382.12 $cm^{2}$

Area of trapezium is 382.12 $cm^{2}$

Area of rectangle = length × width

= 5 × 2

= 10 $cm^{2}$

Area of rectangle = 10 $cm^{2}$

Therefore,

area of the composite figure = 382.12 + 10

= 392.12 $cm^{2}$

8 0

3 years ago