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Ainat [17]
2 years ago
5

WILL MARK BRAINLY! The population of a particular city is given by the function P(t) = 82,100(1.02), where t is the time in year

s and P(t) is the population after t years. What is the current population, the percentage growth rate, and the population size (rounded to the nearest whole person) after 15 years?
Hint: Percentage Growth Rate = r × 100 in A= A0(1 + r)^t

○ 82,100, 2% semiannually, 110,658
○ 82,100, 10.2% annually, 352,425
○ 82,100, 2% annually, 110,496
○ 82,100, 20% semiannually, 985,200​
Mathematics
1 answer:
Tcecarenko [31]2 years ago
3 0

Answer:

P(t) = 82,100(1.02)^t

 1.t is the time in years  

 

2.P(t) is the population after t years

 

3. 100%=1       102-100=2% so the interest rate is 2 %

   102%=1.02

 

4. after 15 year just put in term s of 't' (wich is represent the years) 15 :

Step-by-step explanation:

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uranmaximum [27]
So if it is simple interest then
700+6 times (8% of 700)=answer

percent means partsout of 100
8%=8/100=0.08
'of' means mutily
700+6 times (0.08 times 700)=700+6 times (0.56)= 700+3.36=703.36
answer is $703.36
3 0
2 years ago
a truck that can carry no more than 6400 lb is being used to transport refrigerators and upright pianos. Each refrigerator weigh
Tems11 [23]
I'm not going to do the entire question, but I'll do the first part.

For the first part, you have to set up an inequality. Use context clues, such as no more than (the one used in this sentence) to figure out what the symbol should be for the inequality.
In this case, because it is NO MORE THAN 6400, it would be:

6400\leq250r + 475p

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Now that you have the equation, make the graph, then for the 3rd part, plug in 12 and 8 to r and p to see if it keeps the inequality true.

Hope this helps! :)
7 0
3 years ago
Read 2 more answers
The Wonderful Widget Company's earnings have declined to the point where they need to reduce the number of employees from 1500 1
AleksandrR [38]

Answer:6%

Step-by-step explanation:

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7 0
3 years ago
What is the answer? -9=3+6x
HACTEHA [7]
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-9=3+6x
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-12=6x
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6 0
3 years ago
The weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 pounds.Refer to
Dafna11 [192]

Given that

the weight of football players is distributed with a mean of 200 pounds and a standard deviation of 25 pounds.

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Two standard deviations = 2 x 25 pounds = 50 pounds

So the minimum weight = 200 pounds - 50 pounds = 150 pounds

Hence the final answer is 150 pounds.

3 0
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