<span>Answer:
MgF2 ====⇒ Mg+2 + 2F-
Ksp = [Mg+2][F-]^2
Let S = molar solubility of MgF2
[Mg+2] = S ; [F-] = 2s
Since the [F-] is initially 0.40 M, then [F-] = 0.40 + 2S
6.4 x 10^-9 = (S) (0.40 + 2S)^2 ; one can neglect the 2S in the 0.40 + 2S expression since it is very, very small compared to the 0.40 already present.
6.4 x 10^-9 = S(0.40)^2
S = 4.0 x 10^-8
Molar solubility = 4.0 x 10^-8</span>
I don’t know if this is correct but about 4 times because
3/4 -> 18/24 and 1/6 -> 4/24
Answer:
3/4
Step-by-step explanation:
To answer this question we must first calculate the area of GHJK:
- A= GH*HJ
- A= (LM/2)* (MN/2)
- A= LM*MN/4
- LM/MN is the area of LMNO
- So the area of LMNO is 4 times the area of GHJK
- A is the area of LMNO and S the area of GHJK
- S= A/4
- A-S= A-A/4 = 3A/4
- so the area that is not shaded is 3/4
