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Neporo4naja [7]
3 years ago
12

I really need a tutor, but I don’t have the option, help:(

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
3 0

Answer:

EeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEe

Step by Step Explanation:

EeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEeEe

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Which of the following functions is equal to
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Sarah borrowed some money from her father at a simple interest rate of 5.5% to pay for her college tuition. At the end of the ye
gavmur [86]
\bf ~~~~~~ \textit{Simple Interest Earned Amount}
\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &\$2555\\
P=\textit{original amount deposited}\\
r=rate\to 5.5\%\to \frac{5.5}{100}\to &0.055\\
t=years\to &1
\end{cases}
\\\\\\
2555=P[1+(0.055)(1)]\implies \cfrac{2555}{1+(0.055)(1)}=P
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3 years ago
Classify each number as rational or irrational. Drag the choices into the boxes to correctly complete the table.
Alex17521 [72]

Answer:

3 = irrational

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0 = rational

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7 0
3 years ago
Read 2 more answers
F(x)=x2 what is g(x)?
Oksi-84 [34.3K]

g(x) = (1/4)x^2 . correct option C) .

<u>Step-by-step explanation:</u>

Here we have , f(x)=x^2  and we need to find g(x) from the graph . Let's find out:

We have ,  f(x)=x^2   . From the graph we can see that g(x) is passing through point (2,1 ) . Let's substitute this point in all of the four options !

A . g(x) = (1/4x)^2

Putting (2,1) in equation g(x) = (x/4)^2 , we get :

⇒ g(2)= (\frac{2}{4} )^2

⇒ 1\neq \frac{1}{4}

Hence , wrong equation !

B . g(x) = 4x^2

Putting (2,1) in equation g(x) = 4x^2 , we get :

⇒ g(2)=4(2)^2

⇒ 1\neq 64

Hence , wrong equation !

C . g(x) = (1/4)x^2

Putting (2,1) in equation g(x) = (1/4)x^2 , we get :

⇒ g(2)= (\frac{1}{4} )2^2

⇒ 1= 1

Hence , right equation !

D . g(x) = (1/2)x^2

Putting (2,1) in equation g(x) = (1/2)x^2 , we get :

⇒ g(2)= (\frac{1}{2} )2^2

⇒ 1\neq 2

Hence , wrong equation !

Therefore , g(x) = (1/4)x^2 . correct option C) .

8 0
3 years ago
X= -1/5; f(x) = (25/2)x + (-91/2) =
Diano4ka-milaya [45]

Answer:

Write the problem as a mathematical expression.

X=−1/5; f(x)=(25/2)x+(−91/2)

Replace the variable x with x=−1/5 in the expression.

f(−1/5)=(25/2)(−1/5)−91/2

Simplify the result.

−48

Step-by-step explanation:

4 0
2 years ago
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