Answer:
Mean 24, standard error 0.8
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean
and standard deviation
, the sample means with size n of at least 30 can be approximated to a normal distribution with mean
and standard deviation, also called standard error ![s = \frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=s%20%3D%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
In this problem, we have that:
![\mu = 24, \sigma = 6.4, n = 64](https://tex.z-dn.net/?f=%5Cmu%20%3D%2024%2C%20%5Csigma%20%3D%206.4%2C%20n%20%3D%2064)
What are the mean and the standard error of the sample mean?
By the Central Limit Theorem, mean 24 and standard error ![s = \frac{6.4}{\sqrt{64}} = 0.8](https://tex.z-dn.net/?f=s%20%3D%20%5Cfrac%7B6.4%7D%7B%5Csqrt%7B64%7D%7D%20%3D%200.8)
A and b cause there both half’s
Answer:
I think it's the 3rd one
Step-by-step explanation:
because it makes sense
A stem and leaf plot shows sets of two digit numbers, by separating the ten’s place and the one’s place. On the left is the different ten’s values, while on the right next to each of the values on the left is the one’s values that associate with each of the ten’s values. This means that the numbers in this set of data are 32, 47, 51, 55, 55, 55, 58, 64, and so on. From there, you can use that knowledge to figure out how many scores were above 60.
The terms that are above 60 are 64, 65, 73, 74, 77, 87, 88, 91, 93, 93, 97, 99, and 99, for a total of 13 of the 20 scores being above 60.
Center: 0,0
vertex: 5,0
vertex2 (-5,0)