Answer:
ha
Step-by-step explanation:
ha
First of all we have to arrange the data in ascending order as shown below:
28, 40, 43, 43, 45, 50, 50
Total number of values = 7
Since the number of values is odd, the median will be the middle value i.e. 4th value which is 43. Median divides the data in two halves:
1st Half = 28, 40, 43
2nd Half = 45, 50, 50
Q1 or the First Quartile is the middle value of the lower or 1st half which is 40.
Q3 or the Third Quartile is the middle value of the upper or second half, which is 50.
IQR or the Inter Quartile Range is the difference of Q3 and Q1.
So, IQR= Q3 – Q1 = 50 – 40 = 10
Thus, IQR for the given data is 10
Answer: 3t²(2st⁷ - s⁶ - 2t⁵)
<u>Step-by-step explanation:</u>
5s⁶t² + 6st⁹ - 8s⁶t² - 6t⁷ <em>5s⁶t² and - 8s⁶t² are like terms which = -3s⁶t² when combined</em>
= 6st⁹ - 3s⁶t² - 6t⁷ <em>next, factor out the GCF of 3t²</em>
= 3t²(2st⁷ - s⁶ - 2t⁵)
nshs = sshs+5
wshs = nshh + 6 = sshs + 11
So nshs + wshs + sshs = 3*sshs + 16
So sshs = 10, nshs = 15 and wshs = 21
Answer 15.
Answer:
x + y = 36.....Equation 1
x = 7 + 2y...... Equation 2
Step-by-step explanation:
Let the number of:
Orange goldfish = x
Black gold fish = y
Anna has a total of 36 goldfish in her aquarium, some are orange and some are black.
x + y = 36.....Equation 1
The number of orange goldfish is 7 more than twice the number of black goldfish.
x = 7 + 2y...... Equation 2
We can rewrite this as:
x - 2y = 7..... Equation 2
The system of equations below that can be used to describe the number of black and orange goldfish in Anna's aquarium is :
x + y = 36.....Equation 1
x = 7 + 2y...... Equation 2
