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brilliants [131]
3 years ago
9

(ANSWER ASAP) Solve the inequality. ​

Mathematics
1 answer:
Maurinko [17]3 years ago
6 0

Answer:

Step-by-step explanation:

k ≤ -3-8 subtract 8 from both sides

k ≤ -11

the solution is the area to the left of a vertical line trough the point x= -11 and includes thhe line

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Need help with this problem for my cousin
yKpoI14uk [10]
You have separated the figure into three (3) parts. There are two squares (or rectangles on the bottom. Subtract 5 from 8 to find out the length of the side (right side). 8-5=3. Then subtract 3 from 8 (8-3=5). The new length is 5 ft. 5 multiplied by 5 is the area of one of the squares on the bottom (25 ft. squared). Multiply that by two to find the area of both the squares on the bottom (50 ft. squared).

There's also a rectangle on the top. The base is 15 ft. and the height is 3 ft. Remember that you subtracted 5 from 8 to find out the area of the two bottom squares. 15 multiplied by 3 is 45 (ft.)

Add 45 to 50 to get the area of the entire figure. (45+50=95 or 95 ft. squared).

95 ft. squared is the area of the entire figure. Hope this helped you.
3 0
3 years ago
Round off the number 5028.563 to the nearest thousand
konstantin123 [22]

Answer:

5000

Step-by-step explanation:

Because this is to the nearest THOUSAND, you know you are looking for numbers like 1000, 2000, etc. And you see that with 5028.563, it is below 5500, so you do not round up to 6000, so yoyu must round down to 5000.

8 0
3 years ago
Which of the following is a solution to 2cos2x − cos x − 1 = 0?
Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, x = 0^{\circ}

Step-by-step explanation:

Given that : 2\cos^2x -\cos x -1 =0

Let \cos x =y

then our equation become;

2y^2-y-1= 0           .....[1]

A quadratic equation is of the form:

ax^2+bx+c =0.....[2] where a, b and c are coefficient and the solution is given by;

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}

Simplify:

y = \frac{ 1 \pm \sqrt{1+8}}{4}

or

y = \frac{ 1 \pm \sqrt{9}}{4}

y = \frac{ 1 \pm 3}{4}

or

y = \frac{1+3}{4} and y = \frac{1 -3}{4}

Simplify:

y = 1 and y = -\frac{1}{2}

Substitute y = cos x we have;

\cos x = 1

⇒x = 0^{\circ}

and

\cos x = -\frac{1}{2}

⇒ x = 120^{\circ} \text{and} x = 240^{\circ}

The solution set:  \{0^{\circ}, 120^{\circ} , 240^{\circ}\}

Therefore, the solution for the given equation  2\cos^2x -\cos x -1 =0 is, 0^{\circ}





8 0
3 years ago
Read 2 more answers
Madelyn is knitting a scarf for a holiday gift. So far, it's 4.5 centimeters long. She plans to
olchik [2.2K]

In order to make the question true the length should be 45cm not 4.5 cm , Solving accordingly

  • Let nights be x
  • Rate of change=5cm

The equation is

  • y=45-5x

As 45 is base amount we used it as y intercect

7 0
2 years ago
Will give 20 brainly PLEASE NEED HELP NOW<br> plz put the answer as simple as a b c or d
Bogdan [553]

Answer:

1. A

2. C

Step-by-step explanation:

6 0
3 years ago
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