Answer:
The percent probability of winning a prize=40%.
and not winning prize=60%.
We are asked to find the probability that Hannah only has to buy 3 or less boxes before getting a prize.
Let the random used is x=0,1,2,3 ( where
- 0 denotes that we got the success in first attempt.
- 1 denotes that first bag does not contain prize but we get success in second attempt.
- 2 denotes that we did not get success in 2 attempts but in third we get the success.
- 3 denotes that the success is not obtained in any of the three attempts )
Hence, the probability that the first box will contain prize=![\dfrac{40}{100}](https://tex.z-dn.net/?f=%5Cdfrac%7B40%7D%7B100%7D)
The probability that the first box will not contain prize but second will=![\dfrac{60}{100}\times\dfrac{40}{100}](https://tex.z-dn.net/?f=%5Cdfrac%7B60%7D%7B100%7D%5Ctimes%5Cdfrac%7B40%7D%7B100%7D)
The probability that the first and second box will not contain prize but third will=![\dfrac{60}{100}\times\dfrac{60}{100}\times\dfrac{40}{100}](https://tex.z-dn.net/?f=%5Cdfrac%7B60%7D%7B100%7D%5Ctimes%5Cdfrac%7B60%7D%7B100%7D%5Ctimes%5Cdfrac%7B40%7D%7B100%7D)
The probability that the first and second box will not contain prize but third will=![\dfrac{60}{100}\times\dfrac{60}{100}\times\dfrac{40}{100}](https://tex.z-dn.net/?f=%5Cdfrac%7B60%7D%7B100%7D%5Ctimes%5Cdfrac%7B60%7D%7B100%7D%5Ctimes%5Cdfrac%7B40%7D%7B100%7D)
The probability that the prize is not contained in first, second and third box=![\dfrac{60}{100}+\times\dfrac{60}{100}\times\dfrac{60}{100}](https://tex.z-dn.net/?f=%5Cdfrac%7B60%7D%7B100%7D%2B%5Ctimes%5Cdfrac%7B60%7D%7B100%7D%5Ctimes%5Cdfrac%7B60%7D%7B100%7D)
Hence, the total probability=
![\dfrac{40}{100}+\dfrac{60}{100}\times\dfrac{40}{100}+\dfrac{60}{100}\times\dfrac{60}{100}\times\dfrac{40}{100}+\dfrac{60}{100}+\times\dfrac{60}{100}\times\dfrac{60}{100}](https://tex.z-dn.net/?f=%5Cdfrac%7B40%7D%7B100%7D%2B%5Cdfrac%7B60%7D%7B100%7D%5Ctimes%5Cdfrac%7B40%7D%7B100%7D%2B%5Cdfrac%7B60%7D%7B100%7D%5Ctimes%5Cdfrac%7B60%7D%7B100%7D%5Ctimes%5Cdfrac%7B40%7D%7B100%7D%2B%5Cdfrac%7B60%7D%7B100%7D%2B%5Ctimes%5Cdfrac%7B60%7D%7B100%7D%5Ctimes%5Cdfrac%7B60%7D%7B100%7D)
Answer:
380m²
Step-by-step explanation:
11²+π≈380m²
9 tenths - 3 tenths = 6 tenths. this is true the same way that 9 minus 3 = 6. In reality the tenths make both numbers decimals, but in this case the "tenths" is just a classification of the number and it doesn't effect the answer.
Answer:
x = 7
Step-by-step explanation:
Let's join A & C . If points A ,B & C are collinear , then definitely B point's gonna lie on line segment AC .
So , AC = AB + BC
In the question , length of AC = 3x + 3 , length of AB = 2x - 1 ( or -1 + 2x)
& length of BC = 11.
We know that AC = AB + BC . So putting the given values here :-
![3x+3 = 2x -1 + 11\\=>3x +3 = 2x+10\\](https://tex.z-dn.net/?f=3x%2B3%20%3D%202x%20-1%20%2B%2011%5C%5C%3D%3E3x%20%2B3%20%3D%202x%2B10%5C%5C)
Solving this linear eqn. gives
![3x + 3=2x+10\\=> 3x-2x=10-3\\=>x=7](https://tex.z-dn.net/?f=3x%20%2B%203%3D2x%2B10%5C%5C%3D%3E%203x-2x%3D10-3%5C%5C%3C%2Fp%3E%3Cp%3E%3D%3Ex%3D7)
Answer:
Discount selling price= $172.5
Step-by-step explanation:
Giving the following information:
Selling price= $230
Discount rate= 25%
<u>To calculate the discount selling price, we need to use the following formula:</u>
Discount selling price= selling price*(1 - discount rate)
Discount selling price= 230* (1-0.25)
Discount selling price= $172.5