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Aleksandr-060686 [28]
3 years ago
8

Please Hurry) Consider the quadratic equation 3x^2 - 6 = 2x. A) What is the value of the discrimination? B) What does the discri

mination of the quadratic equation tell about the solutions to 3x^2 - 6 = 2x?. ( Will Mark Brainliest). Show your work. ​
Mathematics
1 answer:
Levart [38]3 years ago
3 0

Answer:

A. 76

B. We will get two real solutions for the equation.

Step-by-step explanation:

A

For any quadratic equation ax²+bx+c=0, the discriminant is b²-4ac.

In 3x²-2x-6=0, a=3, b=-2 and c=-6:

b²-4ac

(-2)²-4(3)(-6)=4+72=76

B.

When the discriminate is positive we get two real solutions to the equation, when it's zero we get one real solution, and when it's negative we get two complex solutions. Since our discriminate, 76, is positive, we know that we will get two real solutions to 3x²-6=2x.

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What is the equation in vertex form of the quadratic function with a vertex at (-1, -4) that goes through (1, 8)?
cestrela7 [59]

Answer:

y = 3(x+1)^2 - 4

Step-by-step explanation:The general form of the equation of a quadratic function whose vertex is (h,k) and whose leading coefficient is a is:

y - k = a(x-h)^2, or

y      = a(x-h)^2 - k

Substituting the coefficients of the vertex (-1, -4), we get:

y      = a(x + 1)^2 - 4

Substituting the coordinates of the given point, (1,8), we get:

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8      = a(2)^2 - 4, or

8  = 4a - 4.  Then 4a = 12, and a = 3.

Thus, the desired equation is y = 3(x+1)^2 - 4 (answer j).


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