Ken's distance is: d(t)=1.7t
Ken's shadow is:
(14-6)/d(t)=14/s
8/d(t)=14/s
s=14d(t)/8
s=1.75d(t) and using the value for d(t) we have:
s=1.75(1.7t)
s=2.975t and if you want it in terms of d, d=1.7t, t=d/1.7 so
s=2.975(d/1.7)
s=1.75d
Answer:
∠DFE ≅ ∠DFG
Step-by-step explanation:
we know that
Triangles are congruent by SAS, if any pair of corresponding sides and their included angles are equal in both triangles
In this problem we have that
The pair of corresponding sides that are equal are
EF=GF and DF (is the same side for both triangles)
The included angle are ∠DFE and ∠DFG
therefore
The additional information needed to prove that triangles DEF and DGF are congruent by SAS is that angles ∠DFE and ∠DFG are equal
so
∠DFE ≅ ∠DFG
Answer:
13.5
hope it helpeddddd
:P
Step-by-step explanation:
