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4 years ago

Find the hypotenuse of a right triangle with legs measuring 4 and 5ft

Mathematics

2 answers:

tangare [24]4 years ago

6 0

The hypotenuse would be square root of 41

BaLLatris [955]4 years ago

4 0

Answer:

The answer is 6.40

Step-by-step explanation:

A squared+ B squared = C squared.

4 squared + 5 squared equals c squared.

16 + 25 = C squared.

41 = C squared.

Square root 42 and the answer is 6.40

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Please help with math

kykrilka [37]

Answer:

2nd option, x > 1.10

Step-by-step explanation:

$7e^{2x}-5 > 58$

Add 5 to both sides,

$7e^{2x}-5+5 > 58 +5\\7e^{2x} > 63$

Divided both sides by 7,

$\frac{7e^{2x}}{7} > \frac{63}{7}$

$e^{2x} > 9$

Apply Exponent Rule,

$2x > 2ln(3)$

$\frac{2x}{2} > \frac{2ln(3)}{2}$

x > ln(3) or x > 1.09861

Learn more about logarithms here: brainly.com/question/12049968

5 0

2 years ago

Isla flipped a coin 30 times. The coin landed heads up 9 times and tails up 21 times.

Debora [2.8K]

Answer:

both are equal

Step-by-step explanation:

there are two side tails and heads so there a 1/2 chance it will land on heads

8 0

3 years ago

What two numbers add to 4 and multiply to 1

Arlecino [84]

There are no numbers for this, thus you will have to use the quadratic formula.

4 0

3 years ago

Explain how you got the answer

Gnoma [55]

Answer:

$\huge\boxed{Center = (3,3),Radius = 2\sqrt{15} }$

Step-by-step explanation:

<u><em>Given equation is</em></u>

$x^2 + y^2 -6x-6y -42 = 0$

Adding 42 to both sides

$x^2 + y^2 -6x-6y = 42\\$

Completing squares

$x^2 -6x+y^2 -6x = 42\\(x)^2 - 2(x)(3) +y^2 - 2(y)(3) = 42$

Adding (3)² => 9 and (3)² => 9 to both sides

$(x-3)^2+(y-3)^2 = 42+9+9\\(x-3)^2 + (y-3)^2 = 60\\(x-3)^2 (y-3)^2 = (2{\sqrt{15})^2}$

Comparing it with $(x-h)^2+(y-k)^2 = r^2$ where Center = (h,k) and Radius = r

We get:

Center = (3,3)

Radius = $2\sqrt{15}$

7 0

3 years ago

The path of a roller coaster over a particular length of track can be represented by a quadratic function f, where f(x) represen

alexgriva [62]

The roller coaster could be represented by the function for Choice D.

If you were to graph this function, you would find that the zeros (x-intercepts) of the function are at the points of -2 and 1. Those are the needed points in the problem.

Since this is a parabola that opens upward, the parabola must be below the axis (or support bar) between those values.

8 0

3 years ago