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Anestetic [448]
3 years ago
8

Kurt deposited money into his bank account every month. The amount of money he deposited in the first 5 months of 2014 is listed

in the table.
Month Amount Deposited
(dollars)
January 1,200.32
February 985.43
March 1,200.65
April 1,987.34
May 1,000.98
The total amount of money that Kurt had deposited into his account at the end of May is ______
The total amount of money that he had deposited into his account at the end of March is _______
Mathematics
2 answers:
Irina-Kira [14]3 years ago
3 1

Answer:

that is the answer

Step-by-step explanation:

zimovet [89]3 years ago
4 0
You have the answer I’m pretty sure
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The sum of the square of a positive number and the square of 3 more than the number is 89. What is the​ number?
Bumek [7]

Answer:

\sqrt{x} +3x=89

Step-by-step explanation:

<em>                                                   not available</em>

4 0
2 years ago
P^3×q^2(p^4×q^n×r^3/r^-4)=p^7q^5r^7 <br><br> What does n=
Juli2301 [7.4K]

Answer:

n = 3

Step-by-step explanation:

Given:

The equation given is:

p^3q^2(p^4q^n\times \frac{r^3}{r^{-4}})=p^7q^5r^7

We simplify the given equation using the following law of indices:

a^m\times a^n=a^{m+n}\\\frac{a^m}{a^n}=a^{m-n}

Therefore,

p^{3+4}q^{n+2}\times r^{3-(-4)})=p^7q^5r^7\\p^7q^{n+2}r^7=p^7q^5r^7\\q^{n+2}=q^5

Since the base on both the sides is same, therefore, their exponents must also be same. This gives,

n+2=5\\n=5-2\\n=3

Therefore, the value of 'n' is 3.

5 0
2 years ago
What six over eight in simplest form
Lilit [14]

3/4


6 divided by 2 = 3

8 divided by 2 = 4  

3 0
3 years ago
The difference between the roots of the equation 3x2+bx+10=0 is equal to 4 1 3 . find<br> b.
inna [77]
Given that the difference between the roots of the equation 3x^2+bx+10=0 is 4 \frac{1}{3} = \frac{13}{3}.

Recall that the sum of roots of a quadratic equation is given by - \frac{b}{a}.

Let the two roots of the equation be \alpha and \alpha + \frac{13}{3}, then 

\alpha + \alpha + \frac{13}{3} =2 \alpha + \frac{13}{3} =- \frac{b}{a} =- \frac{b}{3}  \\  \\ i.e.\ \ 2 \alpha + \frac{13}{3}=- \frac{b}{3} . . . (1)

Also recall that the product of the two roots of a quadratic equation is given by \frac{c}{a}, thus:

\alpha \left( \alpha + \frac{13}{3} \right)= \alpha ^2+ \frac{13}{3} \alpha = \frac{c}{a} = \frac{10}{3}  \\  \\ i.e.\ \ \alpha ^2+ \frac{13}{3} \alpha=\frac{10}{3} . . . (2)

From (1), we have:

2 \alpha =- \frac{b}{3} - \frac{13}{3}  \\  \\ \Rightarrow \alpha =- \frac{b}{6} - \frac{13}{6}

Substituting for alpha into (2), gives:

\left(- \frac{b}{6} - \frac{13}{6}\right)^2+ \frac{13}{3} \left(- \frac{b}{6} - \frac{13}{6}\right)= \frac{10}{3}  \\  \\ \Rightarrow \frac{b^2}{36} + \frac{13b}{18} + \frac{169}{36} - \frac{13b}{18} - \frac{169}{18} = \frac{10}{3}  \\  \\ \Rightarrow \frac{b^2}{36} - \frac{289}{36} =0 \\  \\ \Rightarrow \frac{b^2}{36} = \frac{289}{36}  \\  \\ \Rightarrow b^2=289 \\  \\ \Rightarrow b=\pm\sqrt{289}=\pm17
5 0
3 years ago
How do I answer this question
seraphim [82]
We need to convert 2 kilograms into pounds. First, we find how many pounds are in 1 kilogram.

There are about 2 pounds in one kilogram.

Then we multiply 2 pounds by 2 kilograms to convert the 2 kilograms into pounds.

2 * 2 = 4

So, the answer to this question is 4 pounds.

4 0
3 years ago
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