Two ways:
1) guess factors(trial and error)
2) use quadratic formula.
If you use this method then a = -3, b = -6 and c = -1
x = -b +/- [sqrt(b^2 -4ac)/2a]
substituting a, b, and c into our equation we get:
x = - (-6)+/- [sqrt ((-6)^2) - 4(-3)(-1))/2 (-3)]
x = + 6 +/- [sqrt (36 -4 (3)/-6)] if I didnt make a mistake in my signs
x = + 6 +/- [sqrt (36 -12)/-6)]
x = 6 +/- [sqrt (24)/-6] but sqrt 6 x sqrt of 4 = sqrt 24 hence
x = 6 +/- [ sqrt 6 x sqrt 4 /-6] that is:
x = 6 +/- [sqrt 6 x 2 /-6 ]
so x = 6 + [sqrt 6 x 2/-6] and x = 6 - [sqrt 6 x 2/-6]
Answer:
y = 4 - 2x
Step-by-step explanation:
That is the formula, in y = a + mx but it you want it in y = mx+c, it is y = -2x + 4
The pythagorean theorem states that a^2+ b^2=c^2.
Final answer: None of the above
The answer is D. To solve 3/5 ÷ 4/7 you would change it to 3/5 × 7/4.
1/9 times 2/2=2/18
2/3 times 6/6=12/18
2/18+12/18+5/18=(2+12+5)/18=19/18=1 and 1/8
A is answer
