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3 years ago

If f(x) = 6x – 4, what is f(x) when x = 8?Which represents where f(x) = g(x)?

Mathematics

2 answers:

Alexxx [7]3 years ago

7 0

F(x) = 44 as for having 8 as x

Alex787 [66]3 years ago

4 0

The answer of f(x) when x=8 is 44.

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Answer:

B. -2t^2+3t+4

Step-by-step explanation:

The standard form as

ax^2 + bx + c

Option B meets that requirement, even though it has a '-' in front

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Find a number such that its two-third is equal to 5/4

levacccp [35]

Answer:

x = 15/8.

Step-by-step explanation:

Create an equation, let the number be x:

2/3 * x = 5/4

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3 years ago

Harvey bought a. Frame in which he put his family picture in what is the area of the frame not covered by the picture

9966 [12]

Answer:

Area of the frame not covered with photo is equal to 129 square inches

Step-by-step explanation:

Given: Image of a frame

To find: Area of the frame not covered by the picture

Solution:

Area of rectangle = length of the rectangle × breadth of rectangle

Area of the frame = length of frame × breadth of frame = 23 × 15 = 345 square inches

Area of the frame covered with photo = 18 × 12 = 216 square inches

Area of the frame not covered with photo = Area of the frame - Area of the frame covered with photo = 345 - 216 = 129 square inches

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3 years ago

Car colors preference change over the years and according to the particular model that the customer selects. In a recent year, 1

Margarita [4]

Answer:

99.05% probabilitiy that at most six cars are black.

Step-by-step explanation:

For each luxury car, there are only two possible outcomes. Either it is black, or it is not black. The probability of a luxury car being black is independent from other luxury cars. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$p = 0.1, n = 25$

If 25 cars of that year and type are randomly selected, find the probabilitiy that at most six cars are black.

$P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{25,0}.(0.1)^{0}.(0.9)^{25} = 0.0718$

$P(X = 1) = C_{25,1}.(0.1)^{1}.(0.9)^{24} = 0.1994$

$P(X = 2) = C_{25,2}.(0.1)^{2}.(0.9)^{23} = 0.2659$

$P(X = 3) = C_{25,3}.(0.1)^{3}.(0.9)^{22} = 0.2265$

$P(X = 4) = C_{25,4}.(0.1)^{4}.(0.9)^{21} = 0.1384$

$P(X = 5) = C_{25,5}.(0.1)^{5}.(0.9)^{20} = 0.0646$

$P(X = 6) = C_{25,6}.(0.1)^{6}.(0.9)^{19} = 0.0239$

$P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0718 + 0.1994 + 0.2659 + 0.2265 + 0.1384 + 0.0646 + 0.0239 = 0.9905$

99.05% probabilitiy that at most six cars are black.

7 0

3 years ago