3 years ago

Question 6 (5 points)

1 answer:

6 0

Answer:Estimate the product.

Multiply to find the product. Multiply the decimals as if they were whole numbers. Ignore the decimal point. ...

Compare your estimate with your product to verify that your answer makes sense

Step-by-step explanation:

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Brrunno [24]

$\huge\text{$x=\boxed{\sqrt{33}+4,\ -\sqrt{33}+4}$}$

To solve for $x$ , we need to isolate it on one side of the equation.

Take the square root of both sides, making sure to use both positive and negative roots.

$\begin{aligned}(x-4)^2&=33\\x-4&=\pm\sqrt{33}\end{aligned}$

$\sqrt{33}$ cannot be simplified, so we'll leave it as-is.

Add $4$ to both sides to fully isolate $x$ .

$x=\pm\sqrt{33}+4$

Expand the solution by making two solutions, one where $\sqrt{33}$ is positive and one where it's negative.

$x=\sqrt{33}+4,\ x=-\sqrt{33}+4\\x=\boxed{\sqrt{33}+4,\ -\sqrt{33}+4}$

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Umnica [9.8K]

She had 45$ before she spent it. 30+15

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weqwewe [10]

The weight of the object is only dependent on the strength of gravity on that particular object.

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jonny [76]

3.3 is bigger than 0.8

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Lana71 [14]

Any more details? I cannot know if you don’t have any more details for me

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