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2 years ago

Please answer I will give 20 points!!!

Mathematics

1 answer:

Alenkasestr [34]2 years ago

8 0

The answer is: y= –1/3x–5

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The soccer team played 7 games and scored the following number goals in each game: 2, 1, 3, 5, 3, 1, 4. What was the median numb

soldi70 [24.7K]

Hey there!

Median number :-

Given numbers are

2,1,3,5,3,1,4

Arranging in ascending order,

1,1,2,3,3,4,5

Median = 3

Hope this helps :)

6 0

1 year ago

Read 2 more answers

the library plans to add 1,000 books to its collection if the library can fit 15 books on each foot o shelving will the library

goblinko [34]

Answer: The anwser is 300

Step-by-step explanation:

3 0

2 years ago

Help math math math ASAP

STALIN [3.7K]

<h3>Solution:-</h3>

The equation of any straight line can be written as in slope intercept form as -

$\green{ \underline { \boxed{ \sf{y=mx+c}}}}$

where,

m is its slope
c is its y-intercept.

Given equation:- 

$\begin{gathered}\\\implies\quad \sf 5x+y = 10 \\\end{gathered}$

Arranging it in slope intercept form by transposing 5x to RHS 

$\begin{gathered}\\\implies\quad \sf y = 10 -5x \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf y = -5x +10\\\end{gathered}$

$\leadsto$ Comparing the equation y = -5x +10 with the standard form of the equation, we get -

$\quad \bull\: \sf m= -5$

$\quad \bull \: \sf c= 10$

Thus , 5 is our required answer.

4 0

2 years ago

Read 2 more answers

4)^-5 write in a simplified fraction

erastova [34]

$\bf 4^{-5}?\qquad \textit{well, bear in mind that}\\
----------------------------\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad

\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\\ \quad \\
% negative exponential denominator
a^{{ n}} \implies \cfrac{1}{a^{- n}}
\qquad \qquad 

\cfrac{1}{a^{- n}}\implies \cfrac{1}{\frac{1}{a^{ n}}}\implies a^{{ n}}\\
----------------------------\\
thus\implies 4^{-5}\implies \cfrac{1}{4^{+5}}\implies \cfrac{1}{4^5}\implies \cfrac{1}{1024}$

8 0

2 years ago

When the polynomial in P(x) is divided by (x + a), the remainder equals P(a).

Effectus [21]

According to Remainder Theorem for the polynomials, for every polynomial P(x) there exist such polynomials G(x) and R(x), that $P(x)=(x\pm a)G(x)+R(x)$ .

When the polynomial in P(x) is divided by (x + a), then there exist such polynomials G(x) and R(x), that P(x)=(x+a)G(x)+R(x). Note that for x=-a:

P(-a)=(-a+a)G(-a)+R(-a)=0·G(a)+R(-a)=R(-a).
This means that P(-a) is the remainder, not P(a). 
Answer: correct choice is B.

3 0

2 years ago